Is osmosis the same quality of diffusion but in different molecules

Earth's oceans have an average depth of 3800 m, a total surface area of 3.63 x 108 km2, and an average concentration of dissolve

kakasveta [241]

Answer:

a) Mass of gold in ocean = 8.1*10¹² g

b) Volume of gold = 4.2*10¹¹ cm³

c) Value of gold = $ 4.1*10¹³

Explanation:

a) Depth of ocean = 3800 m

Surface area of ocean = 3.63*10⁸ km²

Now, 10⁶ m² = 1 km²

Therefore, the area in units of m² = 3.63*10¹⁴ m²

$Volume\ of\ ocean = Depth*Area = 3800m*3.63*10^{14} m2=1.4*10^{18} m3$

Average concentration of gold in ocean = 5.8*10⁻⁹ g/L

Now, 1 g/L = 1000 g/m³

Therefore, concentration of gold in g/m³ = 5.8*10⁻⁶ g/m³

$Mass\ of\ gold =1.4*10^{18} m^{3} *5.8*10^{-6} g/m3 = 8.1*10^{12} g$

b) Mass of gold present = 8.1*10¹² g

Density of gold = 19.3 g/cm³

$Volume\ of\ gold = \frac{Mass}{density} =\frac{8.1*10^{12} }{19.3} =4.2*10^{11} cm^{3}$

c) Price of gold = $1595/troy oz

Unit conversion

1 troy oz = 311 g

Therefore, 8.1*10¹² g of gold is equivalent to:

$\frac{8.1*10^{12} g* 1\ troy\ oz}{311g} =2.6*10^{10} \ troy\ oz$

The value of gold in the ocean is:

$\frac{2.6*10^{10} troy\ oz*1595\ dollars}{1\ troy\ oz} =4.1*10^{13} \ dollars$

5 0

4 years ago

When 1 mol of Zn reacts with 0.8 mol of HCI, which of the following will be true?

Cloud [144]

Answer:

Zn is the excess reagent

Explanation:

4 0

3 years ago

The stomach lining is made up of deep muscular grooves. How do you think these structures help the stomach to break down food

dimaraw [331]

The curves absorb the food and sort of squish it and make it easier to digest then the food goes into the stomach acid and kind of burns and become and little softer<span> or in other words by allowing the stomach to stretch in order to accommodate large meals and get grip and move food during the digestion process. </span>

6 0

3 years ago

A chlorine Cl and bromine Br atom are adsorbed on a small patch of surface (see sketch at right). This patch is known to contain

MrRissso [65]

Explanation:

It is given that possible number of ways the Cl and Br can be absorbed initially are 100.

S, possible number of ways by which Br can be desorbed is as follows.

$100 \times 99$