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Aleks04 [339]
4 years ago
8

In a hydrogen atom, the electron and the proton are seperated by about 0.5 angstroms, 5.0×10−11 m. what is the acceleration of a

n electron in this atom?

Chemistry
2 answers:
nadya68 [22]4 years ago
7 0

The charge of proton and electron is equal in magnitude that is 1.6\times 10^{-19} C. The distance between electron and proton is 0.5 \AA or 5\times 10^{-11} m.

Force exerted on electron by proton is calculated as follows:

F= \left | \frac{kq_{e}q_{p}}{r^{2}} \right |

Here, k is Coulomb's constant, q_{p} is charge on proton,  q_{e} charge on electron and r is distance between them.

Putting the values,

F= \left | \frac{(8.99\times 10^{9}N m^{2}/C^{2})(1.6\times 10^{-19} C)(1.6\times 10^{-19} C)}{(5\times 10^{-11} m)^{2}} \right |=9.2\times 10^{-8} N

Now, according to second law of Newton,

F=m_{e}a

Here, m_{e} is mass of electron and a is acceleration.

Also, 1 N=1 kgm/s^{2}

Rearranging,

a=\frac{F}{m_{e}}=\frac{9.2\times 10^{-8} Kg m/s^{2}}{9.11\times 10^{-31} kg}=1.01\times 10^{23} m/s^{2}

Thus, the acceleration of an electron in this atom is 1.01\times 10^{23} m/s^{2}.


uysha [10]4 years ago
4 0

The acceleration of an electron in this atom = a = 1.009.10²⁰ m/s²

<h3>Further explanation</h3>

Rutherford scientists experimented with firing alpha rays on a thin gold plate

From here comes the Rutherford atomic model which states that the initiate consists of positively charged particles and negatively charged electrons around the nucleus

Inside the atom consists of a nucleus containing 3 basic particles namely protons and neutrons, while electrons move around the nucleus.

The charge of 1 proton is equal to a charge of 1 electron, but the sign is different.

The proton is positively charged (+1), the electron is negatively charged (-1). and neutrons not charged (neutral)

For a charge of 1 electron = e = 1.66.10⁻¹⁹ coulomb

Whereas the neutron charge = 0

This atomic unit uses the standard atomic mass, that is, the C-12 isotope

1 C-12 atom = 12 atomic mass units

1 atomic mass unit = 1/12 x mass 1 atom C-12

The mass of 1 proton is equal to the mass of 1 neutron, equal to 1 atomic mass unit and electrons have a smaller mass than both.

electron mass = 9.11.10-28 g

proton mass = 1.6726.10-24 g

neutron mass = 1,675.10-24 g

Coulomb stated the law that between two points / charged particles with a certain distance there is a force that arises between the two points

This style can repel or attract each other

Can be formulated

\large{\boxed{\bold{F=\frac{k.Q1.Q2}{r^2}}}}

k =  8.99 x 10⁹ Nm² / C²

While the electron charge = proton charge = 1.60 x 10⁻¹⁹ C

While the distance from the proton and electron is: 5.0 × 10¹¹ m

So the style that arises is:

F =  8.99 x 10⁹. (1.60 x 10⁻¹⁹)² / (5.0 × 10¹¹)²

F = 9.2.10⁻⁸

Then the acceleration of an electron, from Newtton's Law

a = F/m

a =  9.2.10⁻⁸/ 9.11.10⁻²⁸ g

a = 1.009.10²⁰ m/s²

<h3>Learn more</h3>

resultant velocity

brainly.com/question/4945130

Electromagnetic radiation

brainly.com/question/7590814

Bohr's model of the atom

brainly.com/question/2965079

Keywords : atom, electron, proton, acceleration

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Explanation:

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Preparation:

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<u>Answer:</u> The final concentration of potassium nitrate is 5.70\times 10^{-6}M

<u>Explanation:</u>

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

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Putting values in above equation, we get:

\text{Molarity of }KNO_3=\frac{0.360\times 1000}{101.1\times 500.0}\\\\\text{Molarity of }KNO_3=7.12\times 10^{-3}M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2          .......(1)

  • <u>Calculating for first dilution:</u>

M_1\text{ and }V_1 are the molarity and volume of the concentrated KNO_3 solution

M_2\text{ and }V_2 are the molarity and volume of diluted KNO_3 solution

We are given:

M_1=7.12\times 10^{-3}M\\V_1=10mL\\M_2=?M\\V_2=500.0mL

Putting values in equation 1, we get:

7.12\times 10^{-3}\times 10=M_2\times 500\\\\M_2=\frac{7.12\times 10^{-3}\times 10}{500}=1.424\times 10^{-4}M

  • <u>Calculating for second dilution:</u>

M_2\text{ and }V_2 are the molarity and volume of the concentrated KNO_3 solution

M_3\text{ and }V_3 are the molarity and volume of diluted KNO_3 solution

We are given:

M_2=1.424\times 10^{-4}M\\V_2=10mL\\M_3=?M\\V_3=250.0mL

Putting values in equation 1, we get:

1.424\times 10^{-4}\times 10=M_3\times 250\\\\M_3=\frac{1.424\times 10^{-4}\times 10}{250}=5.70\times 10^{-6}M

Hence, the final concentration of potassium nitrate is 5.70\times 10^{-6}M

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Answer:

The heat absorbed by the sample of water is 3,294.9 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous). Its mathematical expression is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q=?
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Replacing:

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Solving:

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<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>

<u><em></em></u>

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