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bija089 [108]
3 years ago
15

There were 5 chaperones assigned to go

Mathematics
1 answer:
MArishka [77]3 years ago
5 0

Answer:

5 chaperones to 25 students

Step-by-step explanation:

You have to see which expression can be multiplied by 5 since there are 5 chaperones each number of students for example:

5 x 2 = 10

5 x 3 = 15

5 x 4 =20

5 x 5 = 25

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Pls answer this with an explanation if you can pg3 pt12
faust18 [17]
With each gallon you need 11 gallons with 2 parts red 9 parts yellow and since 11x4= 44 you need to do this 4 times
4x2(red)= 8
4x9(yellow)=36
36+8=44
basically 8 gallons of red
i hope this made sense
7 0
3 years ago
41. Which system is represented by the graph?
nekit [7.7K]

Answer:

the answer is the first choice please mark me brainliest

6 0
3 years ago
What is the answer to this problem (x+3)(x+5)
klasskru [66]
Easy, showing work,

using the method FOIL (First,Outer,Inner, Last)

Take, (x+3)(x+5) and multiply,

First,

x*x=x^{2}

Outer,

x*5=5x

Inner,

3*x=3x

Last,

3*5=15

Add the terms together,

x^{2}+8x+15   (x^{2}+5x+3x+15)

Thus, your answer.
4 0
3 years ago
Read 2 more answers
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
2 years ago
For each ordered pair, determine whether it is a solution to the system of equations.
-Dominant- [34]

The only ordered pair that is a solution to the given system of equations is (-2, -6)

<h3>System of Linear Equations </h3>

From the question, we are to determine if each ordered pair is a solution to the given system of equations

The given system of equations is

-9x + 2y = 6

5x - 3y = 8

  • For (7, 9)

That is,

x = 7, y = 9

Putting the values into the first equation

Is -9(7) + 2(9) = 6

-63 + 18 = 6

-45 ≠ 6

Thus, (7,9) is not a solution

  • For (0, 3)

That is,

x = 0, y = 3

Putting the values into the first equation

Is -9(0) + 2(3) = 6

0 + 6 = 6

6 = 6

The ordered pair satisfies the first equation

Testing for the second equation

Is 5(0) - 3(3) = 8

0 - 9 = 8

-9 ≠ 8

Thus, (0, 3) is not a solution

  • For (5, -4)

That is,

x = 5, y = -4

Putting the values into the first equation

Is -9(5) + 2(-4) = 6

-45 - 8 = 6

-53 ≠ 6

Thus, (-5,4) is not a solution

  • For  (-2, -6)

That is,

x = -2, y = -6

Putting the values into the first equation

Is -9(-2) + 2(-6) = 6

18 - 12 = 6

6 = 6

The ordered pair satisfies the first equation

Testing for the second equation

Is 5(-2) -3(-6) = 8

-10 + 18 = 8

8 = 8

The ordered pair satisfies the second equation

∴ The ordered pair that is a solution to the system of equations is (-2, -6)

Hence, the only ordered pair that is a solution to the given system of equations is (-2, -6)

Learn more on System of equations here: brainly.com/question/8630769

#SPJ1

3 0
1 year ago
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