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balu736 [363]
3 years ago
9

If you do this you are officially skilled: (SAT Prep) In the figure, if PN = LN, NP Is parallel to MQ, and QL bisects ∠PQM, what

is value of x?

Mathematics
2 answers:
kumpel [21]3 years ago
8 0

Answer:

67º

Step-by-step explanation:

IgorC [24]3 years ago
5 0

Answer:

Try the suggested solution, shown on the picture attached

Step-by-step explanation:

Note, 'm(MNO)' means m(∠MNO), and for issues 2, 4 ,5 - the described angles are angles inside the declared triangle.

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exactly 12:00 midnight on a 24hour clock is represented as 00:00

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Christopher would be able to make 18 scarves.

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Read 2 more answers
A recommendation for wheelchair ramps is that the rise-to-run ratio be no greater than 1:12. This ensures that the ramps are nav
patriot [66]

Answer:

a. 12 feet b. 12 feet 0.5 inches c. 8.33 %

Step-by-step explanation:

a. How far out horizontally on the ground will it protrude from the building?

Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.

So, by ratios rise/run = 1/12 = 12/x

1/12 = 12/x

x = 12 × 12

x = 144 inches

Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet

b. How long should the ramp be?

The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.

So, L = √(12² + 144²)

= √[12² + (12² × 12²)]

= 12√(1 + 144)

= 12√145

= 12 × 12.042

= 144.5 inches

Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches

c. What percent grade is the ramp?

The percentage grade of the ramp = rise/run × 100 %

= 12 inches/144 inches × 100 %

= 1/12 × 100 %

= 0.0833 × 100 %

= 8.33 %

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3 years ago
man needed money for college he borrowed $7000 at 12% simple interest per year if he paid $210 interest what was the duration of
Dmitry [639]
It is 3 months of duration
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4 years ago
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