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enyata [817]
3 years ago
12

If the theoretical yield of RX is 56.0 g , what is the percent yield ?

Chemistry
1 answer:
maks197457 [2]3 years ago
4 0
the complete question in attached figure

Let 
x------------------- >  actual yield
y------------------- > theoretical yield 
z------------------- > percent yield
we have that
z=x/y

we know
x=47 g
y=56 g

therefore

z=47/56=0.839 ---------------- > 83.9%

the answer is the option C 83.9%

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Complexes containing metals with d10 electron configurations are typically colorless because ________. Complexes containing meta
algol [13]

Answer:

there is no d electron that can be promoted via the absorption of visible light

Explanation:

One of the properties of transition elements is the possession of incompletely filled d orbitals. This property accounts for their unique colours.

The colours of transition metal compounds stem from d-d transition of electrons due to the presence of vacant d orbitals of appropriate energy to which electrons could be promoted.

For elements whose atoms have a d10 configuration, such vacant orbitals does not exist hence their compounds are not colored.

Sometimes, the colour of transition metal compounds stem from ligand to metal charge transfer(LMCT) for instance in KMnO4.

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Of the following two gases, which would you predict to diffuse more rapidly? SO2 or CI2
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Hydrochloric acid reacts with sodium hydroxide to form water and sodium chloride. Hydrochloric acid is an extremely acidic, clea
Brut [27]

The answer is C.

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7 0
3 years ago
How will an increase in wind speed affect soil erosion?
AnnyKZ [126]

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7 0
3 years ago
What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved
Troyanec [42]

Answer:

0.282 M

General Formulas and Concepts:

<u>Chemistry - Solutions</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define</u>

5.85 g KI

0.125 L

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

<u>Step 3: Convert</u>

<u />5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} ) = 0.035241 mol KI

<u>Step 4: Find Molarity</u>

M = 0.035241 mol KI / 0.125 L

M = 0.281928

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.281928 M ≈ 0.282 M

7 0
3 years ago
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