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enyata [817]
3 years ago
12

If the theoretical yield of RX is 56.0 g , what is the percent yield ?

Chemistry
1 answer:
maks197457 [2]3 years ago
4 0
the complete question in attached figure

Let 
x------------------- >  actual yield
y------------------- > theoretical yield 
z------------------- > percent yield
we have that
z=x/y

we know
x=47 g
y=56 g

therefore

z=47/56=0.839 ---------------- > 83.9%

the answer is the option C 83.9%

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Aleks04 [339]

Answer:

Explanation:

According to Bronsted-Lowry acids or base theory ,  the reagent capable of giving hydrogen ion or proton  will be acid and that which accepts hydrogen ion or proton  will be base .

C₉H₇N + HNO₂   ⇄    C₉H₇NH⁺ + NO₂⁻

If K > 1 , reaction is proceeding from left to right .

Hence HNO₂ is giving H⁺ or proton and C₉H₇N is accepting proton to form

C₉H₇NH⁺ .  

Hence HNO₂ is bronsted acid and C₉H₇N is bronsted base .

B )

when K < 1 , reaction above proceeds from right to left . That means

C₉H₇NH⁺ is giving H⁺ so it is a bronsted acid and NO₂⁻ is accepting H⁺ so it is a bronsted base .

Hence ,  NO₂⁻ is a bronsted base and C₉H₇NH⁺ is a bronsted acid .

4 0
3 years ago
If measurements of a gas are 100L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe w
Tanya [424]

Answer:

The pressure of the gas increased (if temperature remained constant).

The Boyle's law supports this observation.

Explanation:

The initial measurements of the gas are given as;

volume = 100 L

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The second measurement is given as;

Volume = 75 L

The second reading implies that the volume of the gas has decreased. If the temperature of the gas remained constant, then the pressure must have increased according to the Boyle's law;

At constant temperature, the pressure of a given mass of an ideal gas is inversely proportional to its volume.

4 0
2 years ago
How do you determine the number of protons in an element
QveST [7]

Answer:

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I am joyous to assist you anytime.

3 0
3 years ago
The molecular weight of NaCl is 58.44 grams/moles. How many grams of NaCl are found in a beaket with 100 ml of a 0.0050 M soluti
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Answer:

The mass of NaCl is 0.029 grams

Explanation:

Step 1: Data given

Molecular weight of NaCl = 58.44 g/mol

Volume of solution = 100 mL = 0.100 L

Molarity = 0.0050 M

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.0050 M * 0.100 L

Moles NaCl = 0.00050 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.00050 moles * 58.44 g/mol

Mass NaCl = 0.029 grams

The mass of NaCl is 0.029 grams

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