Covalent bond is the type of bond which involves the sharing of valence electrons between two atoms.
This bond usually arises from the equal attraction of the nuclei of the two atoms for the electrons shared.
Ionic bond, on the other hand, arises due to the transfer of electrons from the valence shell of one atom to the valence shell of the other.
Answer:
![\boxed {\boxed {\sf PCl_3}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20PCl_3%7D%7D)
Explanation:
We are given the percent composition: 22.5% phosphorus and 77.5% chlorine.
We can assume there are 100 grams of this compound. We choose 100 because we can simply use the percentages as the masses.
Next, convert these masses to moles, using the molar masses found on the Periodic Table.
- P: 30.974 g/mol
- Cl: 35.45 g/mol
Use the molar masses as ratios and multiply by the number of grams. ![22.5 \ g \ P * \frac {1 \ mol \ P }{30.974 \ g \ P}= \frac {22.5 \ mol \ P }{ 30.974} = 0.7264157035 \ mol \ P](https://tex.z-dn.net/?f=22.5%20%5C%20g%20%5C%20P%20%20%2A%20%5Cfrac%20%7B1%20%5C%20mol%20%5C%20P%20%7D%7B30.974%20%5C%20g%20%5C%20P%7D%3D%20%5Cfrac%20%7B22.5%20%5C%20mol%20%5C%20P%20%7D%7B%2030.974%7D%20%3D%200.7264157035%20%5C%20mol%20%5C%20P)
![77.5 \ g \ Cl * \frac {1 \ mol \ Cl }{35.45 \ g \ Cl}= \frac {77.5 \ mol \ Cl }{ 35.45} \ =2.186177715 \ mol \ Cl](https://tex.z-dn.net/?f=77.5%20%5C%20g%20%5C%20Cl%20%20%2A%20%5Cfrac%20%7B1%20%5C%20mol%20%5C%20Cl%20%7D%7B35.45%20%5C%20g%20%5C%20Cl%7D%3D%20%5Cfrac%20%7B77.5%20%5C%20mol%20%5C%20Cl%20%7D%7B%2035.45%7D%20%5C%20%3D2.186177715%20%5C%20mol%20%5C%20Cl)
Divide both of the moles by the smallest number of moles to find the mole ratio.
![\frac {0.7264157035} {0.7264157035} = 1](https://tex.z-dn.net/?f=%5Cfrac%20%7B0.7264157035%7D%20%7B0.7264157035%7D%20%3D%201)
![\frac {2.186177715}{0.7264157035}=3.009540824 \approx 3](https://tex.z-dn.net/?f=%5Cfrac%20%7B2.186177715%7D%7B0.7264157035%7D%3D3.009540824%20%5Capprox%203)
The mole ratio is about 1 P: 3 Cl, so the empirical formula is written as:<u> PCl₃</u>