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AysviL [449]
3 years ago
15

What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved

Chemistry
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

0.282 M

General Formulas and Concepts:

<u>Chemistry - Solutions</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define</u>

5.85 g KI

0.125 L

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

<u>Step 3: Convert</u>

<u />5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} ) = 0.035241 mol KI

<u>Step 4: Find Molarity</u>

M = 0.035241 mol KI / 0.125 L

M = 0.281928

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.281928 M ≈ 0.282 M

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