Explanation:
An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.
Symbol of an alpha particle is
. Whereas a neutron is represented by a symbol
, that is, it has zero protons and only 1 neutron.
Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

Answer:
A
Explanation:
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The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride<span>.
</span><span>The compound AlCl3 is an ionic compound (metal and nonmetal), and therefore does not require prefixes. so AlCl3 is aluminum chloride.
</span><span>
Both of nitrogen and chlorine is nonmetal, but aluminum is metal. Metal with nonmetal will make an ionic compound that doesn't need prefixes.</span>
Answer:
The eccentricity of the ellipse is 0.252.
Explanation:
The eccentricity of an ellipse (
), dimensionless, can be determined by means of the following expression:
(1)
Where:
- Distance between the foci, dimensionless.
- Length of the major axis, dimensionless.
If we know that
and
, then the eccentricity of the ellipse is:


The eccentricity of the ellipse is 0.252.