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Dimas [21]
3 years ago
9

What product(s) are formed during this chemical reaction? (Will be two answers)

Chemistry
1 answer:
lianna [129]3 years ago
3 0

Answer:

BK. BK. BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK BK

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Rina8888 [55]

Answer:

B: it allow quick conversation to others

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3 years ago
Which option is an example of a chemical change?
MA_775_DIABLO [31]
Firework exploding. Thank you :)
6 0
3 years ago
Calculate the concentration of so42− ions in a 0.010 m aqueous solution of sulfuric acid. express your answer to four decimal pl
dimulka [17.4K]
<span>Answer: 0.00649M


The question is incomplete,
</span>

<span>You are told that the first ionization of the sulfuric acid is complete and the second ionization of the sulfuric acid has a constant Ka₂ = 0.012
</span>
<span>
With that you can solve the question following these steps"
</span>

<span>1) First ionization:
</span>
<span>
H₂SO₄(aq) --> H⁺ (aq) + HSO₄⁻ (aq)


Under the fully ionization assumption the concentration of HSO4- is the same of the acid = 0.01 M


2) Second ionization
</span>

<span>HSO₄⁻ (aq) ⇄ H⁺ + SO₄²⁻ with a Ka₂ = 0.012
</span>

<span>Do the mass balance:
</span>


<span><span>        HSO₄⁻ (aq)        H⁺        SO₄²⁻</span>
</span>
<span /><span /><span>        0.01 M  - x          x            x


</span><span>Ka₂ = [H⁺] [SO₄²⁻] / [HSO₄⁻]</span>
<span /><span>
=> Ka₂ = (x²) / (0.01 - x) = 0.012
</span><span />

<span>3) Solve the equation:


</span><span>x² = 0.012(0.01 - x) = 0.00012 - 0.012x</span>
<span /><span>
x² + 0.012x - 0.0012 = 0
</span><span />

<span>Using the quadratic formula: x = 0.00649
</span><span />

<span>So, the requested concentratioN is [SO₄²⁻] = 0.00649M</span>

4 0
4 years ago
Read 2 more answers
A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi
Whitepunk [10]

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

PV=nRT\\\\PV=\frac{w}{M}\times RT

where,

n = number of moles of gas

w = mass of ammonia gas  = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = 27^oC=273+27=300K

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)

w=5.28g

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

8 0
4 years ago
Gabriel and his friend found a piece of metal which they want to
Dominik [7]
50/5.2 that’s the equation that you have to solve then whatever comes out yo calculator is the answer
6 0
3 years ago
Read 2 more answers
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