Question

-) How many atoms are in 0.58 mol of Se?​

Answer 1

Answer:

                      3.50 × 10²³ Atoms of Se

Explanation:

                    As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (atoms) contained by 0.580 moles of Se, we will use following relation,

          Moles  =  Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of Atoms,

          Number of Atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting values,

          Number of Atoms  =  0.580 mol × 6.022 × 10²³ Atoms.mol⁻¹

          Number of Atoms  = 3.50 × 10²³ Atoms

Hence,

          There are 3.50 × 10²³ atoms present in 0.280 moles of Se.