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3 years ago

-) How many atoms are in 0.58 mol of Se?

Chemistry

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

3.50 × 10²³ Atoms of Se

Explanation:

As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as <em>Avogadro's Number</em>. So in order to calculate the number of particles (atoms) contained by 0.580 moles of Se, we will use following relation,

Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of Atoms,

Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting values,

Number of Atoms = 0.580 mol × 6.022 × 10²³ Atoms.mol⁻¹

Number of Atoms = 3.50 × 10²³ Atoms

Hence,

There are 3.50 × 10²³ atoms present in 0.280 moles of Se.

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3 years ago

-) How many atoms are in 0.58 mol of Se?​

-) How many atoms are in 0.58 mol of Se?