3 years ago

using hookes law, F s p r i n g = k^x , find the force needed to stretch a spring 2 cm if it has an elastic constant of 3 N/cm

Chemistry

2 answers:

Shkiper50 [21]3 years ago

7 0

Hooke's Law: F = -kx
F=?
x = 2 cm
k = 3 N/cm

F = -kx = -(3 $\frac{N}{cm}$ ) (2 cm)
F = -6 N

Hope this helps!!

vekshin13 years ago

5 0

Answer:

Why did u ask this

Explanation:

why didn’t I answer this

You might be interested in

Increase the pressure on the system

Molodets [167]

Answer:

What do you mean????????

6 0

3 years ago

Balance the following equation:<br> K+ H2O + H2 + KOH

alex41 [277]

Answer:

2K + 2H2O → H2 + 2KOH

Explanation:

Find how many atoms you have on both sides then add 2 to both sides.

Reactant: Products:

K: 1+1=2 K: 1+1=2

H: 2+2=4 H: 3+1=4

O: 1+1=2 O: 1+1=2

Therefore it is balanced. Hope this helps

6 0

3 years ago

Balanced equations illustrate what law?

Klio2033 [76]

Conservation of mass

8 0

3 years ago

Read 2 more answers

You have an aqueous solution of chromium(III) nitrate that you titrate with an aqueous solution of sodium hydroxide. After a cer

barxatty [35]

Answer:

The precipitate was chromium hydroxide, which then reacted with more hydroxide to produce a soluble complex, Cr(OH)4

Explanation:

The following reaction takes place when chromium(III) nitrate reacts with NaOH:

$Cr(NO)_{3}$ +3 NaOH → $Cr(OH)_{3}$ (s)+ $NaNO_{3}$

The precipitate that is formed is chromium hydroxide, $Cr(OH)_{3}$

When more NaOH is added, the precipitate reacts with it which then results in the formation of a soluble complex ion:

$Cr(OH)_{3}$ (s) + $OH^{-}$ (aq) → $Cr(OH)_{4} ^{-}$ (aq)

$Cr(OH)_{4} ^{-}$ is soluble complex ion

7 0

3 years ago

45.3 in. to millimeters

Stels [109]

1,150.62 millimeters

8 0

3 years ago