Does anyone know the passwords for the flvs 6th grade 04.08 module four test part one and two
2 answers:
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We can figure this out using what's called an explicit formula.
n is the term we are looking for.
f(1) is the first term of the sequence, which in this case, is 100.
d is the common difference, which in this case, is -8.
f(n) = 100 - 8(n - 1)
f(n) = 100 - 8n + 8
f(n) = 108 - 8n
Now, we can input 50 for n and solve.
f(50) = 108 - 8(50)
f(50) = 108 - 400
f(50) = -292
The 50th term in this sequence is -292.
n is the term we are looking for.
f(1) is the first term of the sequence, which in this case, is 100.
d is the common difference, which in this case, is -8.
f(n) = 100 - 8(n - 1)
f(n) = 100 - 8n + 8
f(n) = 108 - 8n
Now, we can input 50 for n and solve.
f(50) = 108 - 8(50)
f(50) = 108 - 400
f(50) = -292
The 50th term in this sequence is -292.