Answer:
![n-3](https://tex.z-dn.net/?f=n%3C-10%2C%20%5C%3A%20n%3E-3)
Interval notation: ![(-\infty, -10)\cup(-3,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%20-10%29%5Ccup%28-3%2C%5Cinfty%29)
Step-by-step explanation:
<u>First inequality:</u>
<u />![n+8](https://tex.z-dn.net/?f=n%2B8%3C-2%2C%20%5C%5Cn%3C-10)
Therefore, this inequality restricts:
![n \in \mathrm{R};\: n](https://tex.z-dn.net/?f=n%20%5Cin%20%5Cmathrm%7BR%7D%3B%5C%3A%20n%3C-10)
<u>Second inequality:</u>
![< 8+n-3](https://tex.z-dn.net/?f=%3C%208%2Bn%3C5%2C%20%5C%5Cn%3E-3)
Therefore, this inequality restricts:
![n \in \mathrm{R};\: n>-3](https://tex.z-dn.net/?f=n%20%5Cin%20%5Cmathrm%7BR%7D%3B%5C%3A%20n%3E-3)
Therefore, with both of these restrictions together, we have:
.
Answer:
X=45
Step-by-step explanation:
X=180-[60+75]=45
Answer:
8 fluid ounces
Step-by-step explanation:
I just got it right on my quiz.
Answer:
c and d
Step-by-step explanation:
a slae price cant be one whole so those are the only reasonable options.
Use distributive property:
(a + b)(c + d) = ac + ad + bc + bd
(y + 1)(y² + 2y + 3) = (y)(y²) + (y)(2y) + (y)(3) + (1)(y²) + (1)(2y) + (1)(3)
= y³ + 2y² + 3y + y² + 2y + 3 = y³ + (2y² + y²) + (3y + 2y) + 3
= y³ + 3y² + 5y + 3