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2 years ago

What is the sum of 4.9 × 102 and 6.8 × 103? 1.17 × 103

Mathematics

2 answers:

Tju [1.3M]2 years ago

7 0

4.9 * 102 = 499.8
6.8 * 103 = 700.4
1.71 * 103 = 120.51

seraphim [82]2 years ago

3 0

Thank you for taking the time and posting your answer on Brainly. Feel free to ask me more questions

(4.9 × 102) + (6.8 × 103) + (1.17 × 103) = 1320.71

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What is an equivalent ratio of 5:9

Goshia [24]

Step-by-step explanation:

There is infinitely many ratios which are equivalent to 5:9. As we know always we can write divide as fraction, so . We can multiply nominator and denominator by the any number (but the same) and get another numbers but ratio will be the same, so equivalent.

For example

10:18,

15:27

Hope this helps.

3 0

2 years ago

Read 2 more answers

Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0

3 years ago

the empire state building is 1250 feet tall. IF an object is thrown upward from the top of the building at an initial velocity o

ss7ja [257]

Answer:

Time for the object to get h(max) s = 1.1875 sec

h (max) = 1272.57 feet

Down time for the object to hit the ground = 4.25 sec

Step-by-step explanation:

The relation

h(s) = - 16*s² + 38* s + 1250 (1)

Is equivalent to the equation for vertical shot

Δh = V(i)*t - 1/2g*t² (in this case we don´t have independent term since the shot is from ground level. We can see in (1), the independent term is 1250 feet ( the height of the empire state building), the starting point of the movement.

The description of the movement is:

V(s) = V(i) - g*s ⇒ V(s) = 38 - 32*s

At h(max) V(s) = 0 38/32 = s

So the maximum height is at s = t = 1.1875 sec

The time for the object to pass for starting point is the same

t = 1.1875 sec

h(max) is

h(max) = - 16* (1.1875)² + 38 (1.1875) + 1250

h(max) = - 22,56 + 45.13 + 1250

h(max) = 1272.57 feet

Time for the object to hit the ground is

h(s) = - 1250 feet

-1250 = - 16 s² + 38*s + 1250

-16s² + 38s = 0

s ( -16s + 38 ) = 0

First solution for that second degree equation is x = 0 which we dismiss

then

( -16s + 38 ) = 0 ⇒ 16s = 38 s = 38/16

s = 2.375 sec and we have to add time between h (max) and to get to starting point ( 1. 1875 sec)

total time is = 2.375 + 1.875

Total time = 4.25 sec

4 0

3 years ago

I need help with this question.

pashok25 [27]

Answer:

B. 9/91

Step-by-step explanation:

-81/9 = -2

9/81 = 1/9

√9 = 3

√81 = 9

B is the odd one out; it's a fraction.

6 0

2 years ago

Find x if segment A B is perpendicular to segment C D in the figure below.

ki77a [65]

If segment AB is perpendicular to segment CD, then a right angle (90°) is formed.

7x + 27 = 90

7x = 63

x = 9

3 0

3 years ago

Read 2 more answers