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Rufina [12.5K]
4 years ago
13

Is groundwater contaminated by sewage from a ruptured septic tank can sometimes be naturally purified by flowing for a relativel

y short distance through a
_ _ __. WHATS THE ANSWER I NEED HELP!!
Chemistry
2 answers:
ANEK [815]4 years ago
8 0

Answer:

Sandstone aquifer

Explanation:

Groundwater is essentially water which is present under the earth's surface and stored in structures called aquifers.

Aquifers are structures that are made of unconsolidated materials (like sand, gravel, slit) or rocks which have the appropriate porosity and permeability for water to flow through. Sandstone aquifers are the most widespread and have the appropriate pore size to trap bacteria in contaminated groundwater. Hence, sewage from a ruptured septic tank can sometimes be naturally purified by flowing for a relatively short distance through a sandstone aquifer.

lora16 [44]4 years ago
6 0
<h2>Answer:</h2>

An Aquifer

<h2>Explanation:</h2>

An aquifer is an underground layer of water-bearing permeable rock or unconsolidated materials like gravel, sand, or silt. The most common aquifers are unconsolidated sands and gravels, permeable sedimentary rocks such as sandstones or limestones and heavily fractured volcanic and crystalline rocks. All of these aquifers can be used for the purification of groundwater contaminated by sewage from a ruptured septic tank.

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Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and hydrosulfuric aci
Helga [31]

Answer:

2OH-(aq) + 2H+(aq) → 2H2O(l)

Explanation:

Step 1: Data given

sodium hydroxide = NaOH

hydrosulfuric acid = H2S

Step 2: The unbalanced equation

NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

Step 3: Balancing the equation

On the left side we have 1x Na (in NaOH), on the right side we have 2x Na (in Na2S). To balance the amount of Na on both sides, we have to multiply NaOH on the left side by 2.

2NaOH(aq) + H2S(aq) → Na2S(aq) + H2O(l)

On the left side we have 4x H (2x in NaOH and 2x in H2S), on the right side we have 2x H (in H2O). To balance the amount of H on both sides, we have to multiply H2O on the right side by 2. Now the equation is balanced.

2NaOH(aq) + H2S(aq) → Na2S(aq) + 2H2O(l)

Step 4: The net ionic equation

2Na+(aq) + 2OH-(aq) + 2H+(aq) + S^2-(aq) → 2Na+(aq) + S^2-(aq) + 2H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

2OH-(aq) + 2H+(aq) → 2H2O(l)

8 0
3 years ago
Sodium metal and water react to create sodium hydrogen and hydrogen gas through the unbalanced equation.
Maurinko [17]

Answer:

Theoretical yield = 2.5 g

Explanation:

Given data:

Mass of sodium = 79.7 g

Mass of water = 45.3 g

Theoretical yield of hydrogen gas = ?

Solution:

Chemical equation:

2Na + 2H₂O → 2NaOH + H₂

Number of moles of sodium:

Number of moles = mass/ molar mass

Number of moles = 79.7 g / 23 g/mol

Number of moles = 3.5 mol

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45.3 g / 18g/mol

Number of moles = 2.5 mol

Now we will compare the moles of hydrogen gas with water and sodium.

                        H₂O           :             H₂

                           2             :              1

                          2.5           :            1/2×2.5 =1.25 mol

                     

                           Na           :              H₂

                             2            :               1

                           3.5           :             1/2×3.5 =1.75 mol

water will be limiting reactant.

Theoretical yield:

Mass = number of moles × molar mass

Mass =  1.25 mol  × 2 g/mol

Mass = 2.5 g

8 0
3 years ago
PLEASE HELP I'LL GIVE YOU BRAINLIEST!!
In-s [12.5K]

Answer:

C

Explanation:

5 0
3 years ago
25.0 mL of an HBr solution were titrated with 29.15 mL of a 0.205 M LiOH solution to reach the equivalence point. What is the mo
trapecia [35]

The molarity of HBr solution is 0.239 M

calculation

write the equation for reaction

that is LiOH +HBr → LiBr +H20

find the moles of LiOH used

moles =molarity x volume

=0.205 x 29.15 = 5.976 moles

by use of mole ratio between LiOH :HBr which is 1:1 the moles of HBr is therefore= 5.976 moles

Molarity of HCL= moles /volume

= 5.976/25 = 0.239 M

7 0
3 years ago
Which of the following ions would represent the ion of an element from Group 1A?
svetoff [14.1K]
The best and the most correct answer among the choices provided by the question is the third choice. The ion that would represent the element from Group 1A is Z+. I hope my answer has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
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