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2 years ago

The ___________________ in the mouth secrete enzymes which help prepare the food for digestion in the stomach.

2 answers:

8 0

The word that should be filled in the blank in order to complete the sentence, "The ______ in the mouth secrete enzymes which help prepare the food for digestion in the stomach." The answer would be saliva. Saliva contains salivary amylase that helps soften the food.

xenn [34]2 years ago

8 0

The salivary glands persent in the oral caity secretes wide range of enzymes that help immensely, in the digestion of the food. This includes, saliva, lysozymes, lingual lipase, and haptocorrin. There are two types of salivary glands: serous glands and mixed glands.

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Given the balanced equation:

Svet_ta [14]

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2 years ago

Potential energy is based on an objects

erma4kov [3.2K]

This is some information about the potential energy.

Explanation:

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2 years ago

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How many formula units make up 36.0 g of magnesium chloride (MgCl2)?

zalisa [80]

Answer: There are $2.29\times 10^{23}$ formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles$

1 mole of $MgCl_2$ contains = $6.023\times 10^{23}$ formula units

Thus 0.38 moles of $MgCl_2$ contains = $\frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23}$ formula units

Thus there are $2.29\times 10^{23}$ formula units

6 0

3 years ago

6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature

sineoko [7]

Answer: The final temperature of the water will be $34.0^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $6832$ Joules

m= mass of water = $5.9mol\times 18g/mol=106.2g$

c = specific heat capacity = $4.184J/g^0C$

Initial temperature of the water = $T_i$ = $18.6^0C$

Final temperature of the water = $T_f$ = ?

Putting in the values, we get:

$6832=106.2\times 4.184\times (T_f-18.6)$

$T_f=34.0^0C$

The final temperature of the water will be $34.0^0C$

8 0

3 years ago

How many particles are present in 12.47 grams of NaCl

liq [111]

Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

Na: 23 g/mole
Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

$moles=\frac{12.47 grams*1 mole}{58.45 grams}$

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

$number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}$

number of particles= 1.26*10²³

1.26*10²³ particles are present in 12.47 grams of NaCl

5 0

3 years ago