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2 years ago

8

The ___________________ in the mouth secrete enzymes which help prepare the food for digestion in the stomach.

2 answers:

lesantik [10]2 years ago

8 0

<span>The word that should be filled in the blank in order to complete the sentence, "The ______ in the mouth secrete enzymes which help prepare the food for digestion in the stomach." The answer would be saliva. Saliva contains salivary amylase that helps soften the food. </span>

xenn [34]2 years ago

8 0

<span>The salivary glands persent in the oral caity secretes wide range of enzymes that help immensely, in the digestion of the food. This includes, saliva, lysozymes, lingual lipase, and haptocorrin. There are two types of salivary glands: serous glands and mixed glands.</span>

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Which statement(s) is/are TRUE about covalent bonds?

tresset_1 [31]

Answer:

1. Covalent bonds can form between two nonmetal atoms.

2. Covalent bonds can form between atoms of the same element.

3. Covalent bonds can form between atoms of different elements.

Explanation:

I hope this helps u! :D

Explanation:

3 0

3 years ago

Balance this chemical equation. NH4OH AlCl3 → Al(OH)3; NH4Cl

skad [1K]

3NH4OH+AlCl3=Al(OH)3+3NH4Cl

7 0

2 years ago

Read 2 more answers

What is the ph of a saturated solution of aluminum hydroxide?

sasho [114]

Answer is attached below ( sorry for mistake )

6 0

3 years ago

What is FeCl3+NaOH=Fe(OH)3+NaCl

nasty-shy [4]

This type of formula is use in chemistry it has Iron ,Sodium, Hydroxyl and Chloride unit s in the equation.
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3 0

3 years ago

Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe

leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

$M_{KOH} = 56.106 \frac{g}{mol}$

<u>Calculate the moles of potassium hydroxide.</u>

$n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}$

$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

$V = 0.5000L$

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

$c = \frac{n}{V}$

$c = \frac{0.25941(9)mol}{0.5000 L}$

$c = 0.5188(3) \frac{mol}{L}$ <= Keep an insignificant figure for rounding

$c = 0.5188 \frac{mol}{L}$ <= Rounded up

$c = 0.5188M$ <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0

2 years ago