In the process of alkoxymercuration, a reaction between an alkene and a alcohol in the presence of mercuric acetate, produces an intermediate called alkoxymercury intermediate. This will react with sodium borohydride, a reducing agent, producing an eter.
In the Williamson Ether Synthesis, occurs a nucleophilic substitution reaction of an alkoxide nucleophile with an alkyl halide. As this is an easier way of producing ethers, it will be more successful than the Alkoxymercuration.
The combustion of ethane is expressed in the balanced reaction C2H6 + 3.5O2= 2CO2 + 3 H2O. Given the mass of oxygen gas, we get the moles of ethane needed by converting this mass to mole (dividing my 32 g/mol), then multiply by 1/3.5 (stioch ratio) and the molar mass of ethane (30 g/mol). The answer is 16.69 grams ethane.
Answer:
because its not international language
Explanation:
because its not international language like English
