The base of a triangle is 7 less than twice its height. if the area of the triangle is 102cm^2 find the length of the base
1 answer:
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Answer:
one side =
Step-by-step explanation:
if you draw an octagon on a piece of paper, you can draw a square around it, you should be able to see a diagram of this attached, ignore the 6.
Let's say TP = a
since it's a regular octagon, TP = HT
and using the Pythagoras Theorem, we know a² + b² = c² and thus:
√(AT² + HA²) = HT
and since AT = HA which we will call x, the equation becomes:
√(2x²) = HT = a
rearrange the equation to solve for x and you get:
2x² = a²
x² =
x =
which, if you rationalise the denominator, you get:
x =
Answer:
<h2>u = 6.88</h2>Solution,
Sinplify the equation using cross multiplication
Calculate the product
Divide both sides of the equation by 17
Calculate
Hope this helps...
Good luck on your assignment..
Answer:
The error is at step (3) .
The correct step (3) will be,
= [by using the laws of indices]
All other steps are correct.
Step-by-step explanation:
The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.
The correct step (3) will be,
= [by using the laws of indices]
All other steps are correct.
Answer:
<h2>cosecθ = 1/sinθ = 11/6√2</h2>Step-by-step explanation:
Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.
Based on SOH, CAH, TOA;
cosθ = adjacent/hypotenuse = 7/11
adjacent = 7 and hyp = 11
Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.
Using pythagoras theorem to get the opposite;
sinθ = 6√2/11
cosecθ = 1/sinθ = 1/( 6√2/11)
cosecθ = 1/sinθ = 11/6√2
Note the error; cscθ 1/cosθ but cscθ = 1/sinθ