Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Answer:
Because you body is introduced to the virus, it is familiar to it and can build up an immunity to the weakened form so when the actual virus invades, your body know what to do.
Explanation:
A mutation can allow a organism to adapt to the environment and example can be the case of the peppered moth which has two variations a white colored one and a black colored one. The white colored ones were able to survive better that the darker ones because of how they were able to camouflage with the lichen located in the trees. However, after a while smoke particles that were released by industries darkened the trunk of the trees making the white moths visible and allowing the darker colored ones to survive. Another example can be on how organism can be resistant to bacteria this allows the animal to survive and reproduce offspring with the same mutation. I hope this helps...
Answer:
A lot
Explanation:
am playing there around 195 counties and 7 continets my bad
