Setup
45t = 40t + 60
5t = 60
t = 12
car A = 45 * 12 = 540 mi
car B = 40 * 12 = 480 mi
Answer:
yes
Step-by-step explanation:
Substitute x = 2 and y = 5 into the left side of the equations and if equal to the right side then they are a solution.
x + 2y = 2 + 2(5) = 2 + 10 = 12 ← True
3x + 6y = 3(2) + 6(5) = 6 + 30 = 36 ← True
Thus x = 2, y = 5 is a solution to both equations
Hello,
Looking at the data, you should go with the second and fourth results.
On the second one, Dr. Appiah's M.A.D. is only 9.7 which is less than Dr. Singh's M.A.D. of 14.1
On the fourth one, Dr. Cantwell and Dr. Singh both have a M.A.D. that is only 0.1 from 14, so their ages vary by about the same amount.
Best of luck,
MrEQ
To transform the function
to have the amplitude of 3, we need to multiply the constant 3 to the function f(x), so we have
To transform the function
to have the midline
we need to subtract
by 4, so we have
,
To transform the function
to have period of
, we need to divide the original period
by 4, so we have
. Note that it is the
gives the effect of dividing the points on x-axes by 4 and the period is read on x-axes
Hence, the full transformation is given
which is the last option
Answer:
<h2>-x²+4x +6</h2>
Step-by-step explanation:
Given f(x)=4x+1 and g(x)=x²-5
(f-g)(x) is derived by taking the difference of both functions
(f-g)(x) = f(x)-g(x)
(f-g)(x) = 4x+1 - (x²-5)
(f-g)(x) = 4x+1-x²+5
(f-g)(x) = -x²+4x +6
This gives the requires expression
