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Mazyrski [523]
3 years ago
9

In which phase is the full illuminated face of the Moon visible on Earth? A) New moon Eliminate B) Full moon C) Waning gibbous D

) Waxing crescent
Physics
1 answer:
Nitella [24]3 years ago
4 0
Full moon

New cant be seen

Gibbous is 3/4

Crescent is 1/4
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(Mass vs. Weight) HELP PLZ!!
Lina20 [59]

\huge \boxed { \sf{Answers}}

  • c. The weight of an object on the moon will be the same as its weight on Earth. It is false because the weight of an on the moon will be 1/6 th times its weight on Earth.
  • d. The weight of an object is its mass multiplied by the force of gravity. The statement is false because the formula of weight is mass × acceleration due to gravity, not force of gravity.
  • e. The mass and weight of an object are the same thing. The statement is false because mass means a body of matter. While weight of an object is its mass multiplied by the force of gravity.
  • f. The mass of an object is the force of gravity acting upon an object. It is false because it will be the weight of the object not mass.
  • So, the answers are c, d, e and f.

Hope you could understand.

If you have any query, feel free to ask.

7 0
2 years ago
A car has a mass of 1000 kg and accelerates at 2 meters per second per second. what is the magnitude of the net force exerted on
9966 [12]
F=ma
Therefore the net force = 1000kg × 2 metres per second per second
So F=2000 N
4 0
3 years ago
Read 2 more answers
A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph
Marina86 [1]

Solution:


initial sphere mvr = final sphere mvr + Iω 
where I = mL²/3 = 2.3g * (2m)² / 3 = 3.07 kg·m² 
0.25kg * (12.5 + 9.5)m/s * (4/5)2m = 3.07 kg·m² * ω 
where: ω = 2.87 rad/s 

So for the rod, initial E = KE = ½Iω² = ½ * 3.07kg·m² * (2.87rad/s)² 
E = 12.64 J becomes PE = mgh, so 
12.64 J = 2.3 kg * 9.8m/s² * h 
h = 0.29 m 

h = L(1 - cosΘ) → where here L is the distance to the CM 
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ 
Θ = arccos((1-0.29)/1) = 44.77 º 

8 0
3 years ago
A boy weighs 40 kilograms. He runs at a velocity of 4 meters per second north. Which is his momentum?
Bogdan [553]
The boy's momentum is 160 kg*m/s north.

The formula of momentum is p = mv, where p is momentum.
p = 40 kg * 4m/s north
p =160 kg*m/s north

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>


4 0
3 years ago
Read 2 more answers
A motor produces less mechanical energy than the energy it uses because the motor?
In-s [12.5K]
<span>A motor produces less mechanical energy than the energy it uses because the motor looses some energy to heat.</span>
3 0
3 years ago
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