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REY [17]
3 years ago
7

HELP is it impossible to experience free fall near the earths surface? why?

Physics
1 answer:
kow [346]3 years ago
3 0
It’s not impossible because the gravitational pull from the earths gravity from the atmosphere will pull you in just like all other planets that’s why you can fall at really fast speeds from the air.
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During its lifespan, what characteristics of the sun will change
4vir4ik [10]
During its lifepsan, the sun's core would keep contracting and heating up.

The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
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3 years ago
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Work of 5 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (i
densk [106]

Answer:

Explanation:

Given that,

5J work is done by stretching a spring

e = 19cm = 0.19m

Assuming the spring is ideal, then we can apply Hooke's law

F = kx

To calculate k, we can apply the Workdone by a spring formula

W=∫F.dx

Since F=kx

W = ∫kx dx from x = 0 to x = 0.19

W = ½kx² from x = 0 to x = 0.19

W = ½k (0.19²-0²)

5 = ½k(0.0361-0)

5×2 = 0.0361k

Then, k = 10/0.0361

k = 277.008 N/m

The spring constant is 277.008N/m

Then, applying Hooke's law to find the applied force

F = kx

F = 277.008 × 0.19

F = 52.63 N

The applied force is 52.63N

6 0
3 years ago
Mains electricity is an ac supply. Explain the difference between direct and alternating potential difference.
Gennadij [26K]

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5 0
3 years ago
Sound
Ann [662]
Longitudinal, because the sound can only travel at one direction
3 0
3 years ago
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Two identical loudspeakers are some distance apart. A person stands 5.80 m from one speaker and 3.90 m from the other. What is t
NikAS [45]

Answer:

f = 632 Hz

Explanation:

As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength

here we know that

\Delta x = (2n + 1)\frac{\lambda}{2}

given that path difference from two loud speakers is given as

\Delta x = 5.80 m - 3.90 m

\Delta x = 1.90 m

now we know that it will have fourth lowest frequency at which destructive interference will occurs

so here we have

\Delta x = 1.90 = \frac{7\lambda}{2}

\lambda = \frac{2 \times 1.90}{7}

\lambda = 0.54 m

now for frequency we know that

f = \frac{v}{\lambda}

f = \frac{343}{0.54} = 632 Hz

7 0
3 years ago
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