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3 years ago

34.1 grams / 1.1 mL =

Physics

1 answer:

nataly862011 [7]3 years ago

6 0

Answer:

31,000kg/m^3

Explanation:

Hopefully this helps

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Why doesn’t the moon fall toward the earth and smash into it?

yarga [219]

Gravity

The moon doesn't smash into the earth because the gravity from the earth keeps the moon in orbit around it.

8 0

3 years ago

in which of the situations listed below is energy being transferred as heat to the system in order for the system to do work? In

In-s [12.5K]

The answer is option A, i think but i am not sure

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3 years ago

Initial velocity vector vA has a magnitude of 3.00 meters per second and points 20.0o north of east, while final velocity vector

garri49 [273]

Answer:

$5.2\ \text{m/s}$

$70^{\circ}$ south of east

Explanation:

$v_a$ = 3 m/s

$\theta_a$ = $20^{\circ}$ north of east

$v_b$ = 6 m/s

$\theta_b$ = $40^{\circ}$ south of east = $360-40=320^{\circ}$ north of east

x and y component of $v_a$

$v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}$

$v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}$

x and y component of $v_b$

$v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}$

$v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}$

$\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}$

Magnitude

$|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}$

Direction

$\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}$

The magnitude of the change in velocity vector is $5.2\ \text{m/s}$ and the direction is $70^{\circ}$ south of east.

6 0

3 years ago

Two forces act on a 6.00- kg object. One of the forces is

Stella [2.4K]

Answer:

Fx = 22N

Explanation:

There are 2 possible scenarios for this problem:

1.- The 10N force is in the same direction of the acceleration. In this case the other force would be:

$F1 - Fx = m*a$ where F1 = 10N, m=6kg, a = 2m/s2

$Fx = F1 - m*a = -2N$ The negative result tells us that this is not possible.

2.- The 10N force is in the opposite direction of the acceleration. In this case the other force would be:

$Fx - F1 = m*a$ $Fx = m*a + F1 = 22N$

3 0

3 years ago

An Olympic-class sprinter starts a race with an acceleration of 5.10 m/s2. What is her speed 2.40 s later?

ivolga24 [154]

Answer:

12.24 m/s

Explanation:

Speed: This can be defined as the rate of change of distance with time. The S.I unit of speed is m/s.

Using the formula,

a = v/t................ Equation 1

Where a = acceleration of the sprinter, v = speed of the sprinter, t = time.

making v the subject of the equation,

v = at ................. Equation 2

Given: a = 5.1 m/s², t = 2.4 s.

Substitute into equation 2

v = 5.1(2.4)

v = 12.24 m/s.

Hence, the speed of the sprinter = 12.24 m/s

3 0

3 years ago