A radioactive isotope of the element potassium decays to produce argon. If the ratio of argon to potassium is found to be 31:1,
1 answer:
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Answer:
KE = 1.75 J
Explanation:
given,
mass of ball, m₁ = 300 g = 0.3 Kg
mass of ball 2, m₂ = 600 g = 0.6 Kg
length of the rod = 40 cm = 0.4 m
Angular speed = 100 rpm=
=10.47\ rad/s
now, finding the position of center of mass of the system
r₁ + r₂ = 0.4 m.....(1)
equating momentum about center of mass
m₁r₁ = m₂ r₂
0.3 x r₁ = 0.6 r₂
r₁ = 2 r₂
Putting value in equation 1
2 r₂ + r₂ = 0.4
r₂ = 0.4/3
r₁ = 0.8/3
now, calculation of rotational energy
KE = 1.75 J
the rotational kinetic energy is equal to 1.75 J
Answer:
Acceleration of proton will be
Explanation:
We have given a proton is placed in an electric field of intensity of 700 N/C
So electric field E = 700 N/C
Mass of proton
Charge on proton
So electric force on the proton
This force will be equal to force due to acceleration of the proton
According to newton's law force is given by F = ma
So
So acceleration of proton will be