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Phantasy [73]
4 years ago
5

A motorist travels for 3.0 h at 80 km/h and 2.0 h at 100 km/h. What is her average speed for the trip?

Physics
2 answers:
USPshnik [31]4 years ago
8 0

Answer:

The motorist average speed for the trip is 88 km/h

Explanation:

In order to know her average speed, we have to refer to the following ecuation:

<V> (average speed) = \frac{Vfinal+Vinital}{2}

So, according to that, we know that the motorist has been having a speed of 80km/h during 3 hours, and a speed of 100 km/h during 2 hours. It means that her speed during all the travel is 5 hours.

Then, we have to affect the 5 hours to the inicial and final speed as follows:

First, at 80 km/h, she travels during 2 hours so:

3h*80km/h= 240 km

And then, at 100 km/h:

2h*100km/h= 200 km

Which leads us to:

initial speed: 240 km/ 5 h= 48 km/h

and final speed of: 200 km/ 5 h= 40 km/h

Then, the average speed is:

<V> = 48 km/h + 40 km/h = 88 km/h

Volgvan4 years ago
6 0
3x80=240
2x100=200
240+200/5=88 k/hr
☺☺☺☺
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Explanation:

It is given that,

Number of turns in primary coil, N_p=60

Number of turns in secondary coil, N_s=300

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Current in primary coil, I_p=2\ A

We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :

\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}

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\dfrac{N_p}{N_s}=\dfrac{I_s}{I_p}

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<em>Hence, this is the required solution.</em>

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The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i
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Answer: The coefficient of kinetic friction is μ = 0.6

Explanation:

For an object of mass M, the weight is:

W = M*g

where g is the gravitational acceleration: g = 9.8m/s^2

And the friction force between this object and the surface can be written as:

F = W*μ

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In this case, the weight is:

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A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field. A deuteron has the same char
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Answer:

The ratio of the acceleration of the proton to that of the deuteron is 2

Explanation:

For a moving charge in magnetic field, the magnetic force is balanced by force due to its motion. So,

qvB=ma

Acceleration of proton,

a_p=\dfrac{qvB}{m_p}  .........(1)

Acceleration of deuteron,

a_d=\dfrac{qvB}{m_d}   ..........(2)

Since, a deuteron has the same charge as the proton but has twice its mass.

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