Start by using the addition as a sign and use multiplying
The concept required to solve this problem is related to the wavelength.
The wavelength can be defined as the distance between two positive crests of a wave.
The waves are in phase, then the first distance is
And out of the phase when
Thus the wavelength is
Here,
Wavelength
If we rearrange the equation to find it, we will have
Therefore the wavelength of the sound is 20cm.
Answer:
Average acceleration = 6m/s²
Explanation:
Given the following data;
Initial velocity, u = 4m/s
Final velocity, v = 22m/s
Time, t = 3 seconds
To find the average acceleration;
Acceleration = (v - u)/t
Substituting into the equation, we have;
Acceleration = (22 - 4)/3
Acceleration = 18/3
Acceleration = 6m/s²
Answer:
20.1 m
Explanation:
First, find the time it takes for the cannonball to travel the horizontal distance of 50.0 m.
Given (in the x direction):
Δx = 50.0 m
v₀ = 68 cos 25° m/s
a = 0 m/s²
Find: t
Δx = v₀ t + ½ at²
(50.0 m) = (68 cos 25° m/s) t + ½ (0 m/s²) t²
t = 0.811 s
Now find the vertical displacement after that time.
Given (in the y direction):
v₀ = 68 sin 25° m/s
a = -9.8 m/s²
t = 0.811 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (68 sin 25°) (0.811 s) + ½ (-9.8 m/s²) (0.811 s)²
Δy = 20.1 m
