1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bija089 [108]
3 years ago
6

Determine the approximate force (N) used to pull a sled up a 400 m hill using 1900 J of work.

Physics
1 answer:
Sergeu [11.5K]3 years ago
4 0
The work done to pull the sled up to the hill is given by
W=Fd
where
F is the intensity of the force
d is the distance where the force is applied.

In our problem, the work done is W=1900 J and the distance through which the force is applied is d=400 m, so we can calculate the average force by re-arranging the previous equation and by using these data:
F= \frac{W}{d}= \frac{1900 J}{400 m} = 4.75 N \sim 5 N
You might be interested in
To model time-variant data, one must create a new entity in an m:n relationship with the original entity.
Ksenya-84 [330]

To model time-variant data, one must create a new entity in an m:n relationship with the original entity, is a False statement.

  • Like the majority of software engineering initiatives, the ER process begins with gathering user requirements. What information must be retained, what questions must be answered, and what business rules must be implemented (For instance, if the manager column in the DEPARTMENT table is the only column, we have simply committed to having one manager for each department.)
  • The end result of the E-R modeling procedure is an E-R diagram that can be roughly mechanically transformed into a set of tables. Tables will represent both entities and relationships; entity tables frequently have a single primary key, but the primary key for relationship tables nearly invariably involves numerous characteristics.

To know more about  entity AND relationship  visit : brainly.com/question/28232864

#SPJ4

6 0
1 year ago
A"car"initially"at"rest"experiences"a" constant"acceleration"along"a"horizontal" road."the"position"of"the"car"at"several" succe
marysya [2.9K]

In the process of peppering the question with those forty (40 !) un-necessary quotation marks, you neglected to actually show us the illustration.  So we have no information to describe the adjacent positions, and we're not able to come up with any answer to the question.

7 0
3 years ago
A light ray transfers from more to less dense medium at certain condition , if we repeat this experiment by increasing the angle
evablogger [386]

Answer:

The correct option is;

Still constant

Explanation:

The relative refractive index ₁n₂ between the two medium can be as follows;

_1n_2 = \dfrac{The \ speed \ of \ light \ in \ medium \ 1}{The \ speed \ of \ light \ in \ medium \ 2}  = \dfrac{c_1}{c_2}

Therefore, given that the speed of light in medium 1 is constant and the speed of light on medium 2 is also constant, the relative refractive index ₁n₂ = c₁/c₂ is always constant.

4 0
3 years ago
Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth? Assume that t
alexandr1967 [171]

Answer:

a) the one with a lower orbit    b) the one with a higher  orbit

Explanation:

Let's consider orbital mechanics. To get an object in orbit, we need it to fall to earth parallel to the earth's surface. To understand it easily imagine a projectile thrown horizontally further and further away, at one point, the projectile hits the cannon from behind. Considering there is no wind resistance, that would be a projecile in orbit.

In other words, the circular orbits of some objects around a massive body are due to the equality between centrifugal acceleration and gravity acceleration.

\frac{v^2}{r} = \frac{GM}{r^2}.

so the velocity is

v = \sqrt{\frac{GM}{r} }

where "G" is the gravitational constant, "M" the mass of the massive body and "r" the distance between the object and the center of gravity of mass M. As you can note, if "r" increase, "v" decrease.

The orbital period of any object in orbit is

T = 2\pi \sqrt{\frac{a^3}{GM} }

where "a" is length of semi-major axis (a = r in circular orbits). So if "r" increase, "T" increase.

3 0
3 years ago
Who was nikola teslas partner​
vesna_86 [32]

Answer:

Thomas Edison

Explanation:

6 0
4 years ago
Read 2 more answers
Other questions:
  • A thin, circular coil of wire of radius r consists of 100 turns of wire carrying a conventional current of I in the counter-cloc
    8·2 answers
  • Carol can be defined as a social drinker because she can easily limit drinking and she chiefly drinks alcohol when she is out wi
    8·2 answers
  • Is y correct? Why or why not?
    11·1 answer
  • Determine o que se pede e diga qual transformaçao P=25 atm T=600 P=75atm T=?
    5·1 answer
  • A plumber heats a plastic pipe, softens it, shapes it, and then lets it cool. After it is hardened, the
    12·1 answer
  • A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
    8·1 answer
  • A mouse jumps horizontally from a box of height 0.25m.  If the mouse jumps with a speed of 2.1 m/s, how far from the box does th
    10·2 answers
  • Plzzzzz helppppp plzzzzzzzzzzzzzzzzzzzzzzz
    11·2 answers
  • Which geologic events occur most often at this mid-oceanic ridge plate
    8·1 answer
  • Question 2 A horizontal line on a position vs time graph means the object is O moving faster. O at rest O slowing down. O moving
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!