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zmey [24]
4 years ago
6

Position coordinate of a particle confined to

Physics
1 answer:
Gelneren [198K]4 years ago
8 0

Answer:

a) 4 s

b) 36 m/s²

c) 54 m

Explanation:

s = 2t³ – 24t + 6

a) Find t when v = 72 m/s.

v = ds/dt

v = 6t² – 24

72 = 6t² – 24

6t² = 96

t = 4

b) Find a when v = 30 m/s.

a = dv/dt

a = 12t

When v = 30:

30 = 6t² – 24

6t² = 54

t = 3

a = 36

c) Find Δs between t = 1 and t = 4

Δs = (2(4)³ – 24(4) + 6) – (2(1)³ – 24(1) + 6)

Δs = 38 – (-16)

Δs = 54

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Answer:

Explanation:

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<u>Answer</u>

46,200 J

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4 0
4 years ago
A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli
goblinko [34]

Answer:

v = 2.974

Explanation:

Perhaps the formula should be

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v = √14.21 * (0.707 - 0.0849)                        Figure out Sin(θ) - uk cos(θ)  

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4 years ago
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3 Below, someone is trying to balance a plank with
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Answer:

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In the figure, we have;

The distance from the point 'O', to the 6 N force = 2 m

The position of the 6 N force relative to the point 'O' = To the left of 'O'

The distance from the point 'O', to the 4 N force = 4 m

The position of the 4 N force relative to the point 'O' = To the right of 'O'

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8 0
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