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zmey [24]
4 years ago
6

Position coordinate of a particle confined to

Physics
1 answer:
Gelneren [198K]4 years ago
8 0

Answer:

a) 4 s

b) 36 m/s²

c) 54 m

Explanation:

s = 2t³ – 24t + 6

a) Find t when v = 72 m/s.

v = ds/dt

v = 6t² – 24

72 = 6t² – 24

6t² = 96

t = 4

b) Find a when v = 30 m/s.

a = dv/dt

a = 12t

When v = 30:

30 = 6t² – 24

6t² = 54

t = 3

a = 36

c) Find Δs between t = 1 and t = 4

Δs = (2(4)³ – 24(4) + 6) – (2(1)³ – 24(1) + 6)

Δs = 38 – (-16)

Δs = 54

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What is the magnitude of the momentum of a 11kg object moving at 2.2 m/s?
tangare [24]

Answer:

<h3>The answer is 24.2 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 11 kg

velocity = 2.2 m/s

We have

momentum = 11 × 2.2

We have the final answer as

<h3>24.2 kgm/s</h3>

Hope this helps you

4 0
3 years ago
HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!​
sleet_krkn [62]

Answer:

a. 25000 J

b. 2500 J/s

Explanation:

Given,

Distance ( s ) = 50 m

Force ( f ) = 500 N

a.

To find : -

Work done ( W ) = ?

Formula : -

W = fs

W

= 500 x 50

= 25000 J

Therefore,

the work done by the force the horse exerts is

25000 J.

b.

To find : -

Power ( P ) = ?

Formula : -

W = Pt

P = W / t

P

= 25000 / 10

= 2500 J/s

Therefore,

the power produced if the movement took 10 s

is 2500 J/s.

3 0
3 years ago
Read 2 more answers
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling
Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

t = 0.672 s

so we can find the vertical velocity by which person will hit the water using kinematics

v_y = u_y + at

v_y = 0 + (9.81)(0.672)

v_y = 6.6 m/s

now the speed of the person at the end of the slide is given as

v = \frac{L}{t}

v = \frac{5}{0.672}

v_x = 7.44 m/s

now by energy conservation we can find the initial height

mgH = \frac{1}{2}m(v_x^2 + v_y^2)

H = \frac{1}{2g}(v_x^2 + v_y^2)

H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)

H = 5 m

6 0
3 years ago
Read 2 more answers
Automobile engines AND steam engines are examples of ______. a. internal combustion engines b. heat engines c. external combusti
uranmaximum [27]

Answer: B. Heat engines

Explanation:

8 0
3 years ago
Read 2 more answers
I forgot how to do this ;;;
Anit [1.1K]

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (10 m/s − 5 m/s) / 4 s

a = 1.25 m/s²

Work = force × distance

First, find the distance traveled.

v² = v₀² + 2aΔx

(10 m/s)² = (5 m/s)² + 2 (1.25 m/s²) Δx

Δx = 30 m

Now find the work:

W = (600 kg × 1.25 m/s²) (30 m)

W = 22,500 J

Alternative, work = change in energy.

W = ΔKE

W = ½ mv² − ½ mv₀²

W = ½ m (v² − v₀²)

W = ½ (600 kg) ((10 m/s)² − (5 m/s)²)

W = 22,500 J

8 0
3 years ago
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