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gayaneshka [121]
3 years ago
6

How much money invested at 5% compounded continuously for 3 years will yield at $820?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer:

Percentage of interest at which the money is invested = 5%

Time for which the money is invested = 3 years

The final amount after 3 years = $820

Let us assume the principal amount = x dollars

We can conclude that the principal amount invested was $708.35.


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Type the correct answer in the box. Use numerals instead of words.
artcher [175]

Answer:

100

Step-by-step explanation:

8 0
3 years ago
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) e number of viewers ordering a particular pay-per-view program is normally distributed. Past history shows that 33.00% of the
lubasha [3.4K]

Answer:

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Past history shows that 33.00% of the time fewer than 20,000 people order the program

This means that X = 20000 has a pvalue of 0.33. So when X = 20000, Z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{20000 - \mu}{\sigma}

20000 - \mu = -0.44\sigma

\mu = 20000 + 0.44\sigma

Only ten percent of the time do more than 28,000 people order the program.

This means that X = 28000 has a pvalue of 1-0.1 = 0.9. So when X = 28000, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{28000 - \mu}{\sigma}

28000 - \mu = 1.28\sigma

\mu = 28000 - 1.28\sigma

Also

\mu = 20000 + 0.44\sigma

So

20000 + 0.44\sigma = 28000 - 1.28\sigma

1.72\sigma = 8000

\sigma = \frac{8000}{1.72}

\sigma = 4651.16

\mu = 20000 + 0.44\sigma = 20000 + 0.44*4651.16 = 22046.5

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

6 0
3 years ago
Lance the alien is 5 feet tall. His shadow is 8 feet lopg.
Stells [14]

Answer:

20 ft

Step-by-step explanation:

The 2 triangles are similar, thus the ratios of corresponding sides are equal.

let h be the height of the tree, then

\frac{h}{5} = \frac{32}{8} = 4 ( multiply both sides by 5 )

h = 20

The height of the tree is 20 ft

3 0
3 years ago
Help plzzzzzzzzzzzzz thank you! , take your time.
Alika [10]

Answer:

Step-by-step explanation:

1. 9  4  5  2  3  5  .  3  2  1  

Ones : 5

Tens : 3

Hundreds : 2

Thousands : 5

Ten Thousands : 4

Hundred Thousands : 9

Tenths : 3

Hundredths : 2

Thousandths : 1

2.  5  6  9  3  4  3  5  .  1  2  3  

Ones : 5

Tens : 3

Hundreds : 4

Thousands : 3

Ten Thousands : 9

Hundred Thousands : 6

Million : 5

Tenths : 1

Hundredths : 2

Thousandths : 3

6 0
3 years ago
What is the answer to this question ? Please answer !!
mylen [45]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ k:y=m_2x+b_2,\ \text{then}\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\-------------------------\\\text{We have}\ 5x-y=-4.\ \text{Convert it to the slope-intercept form:}\\\\5x-y=-4\qquad\text{subtract 5x from both sides}\\\\-y=-5x-4\qquad\text{change the signs}\\\\y=5x+4\to m_1=5\to m_2=-\dfrac{1}{5}\\\\\text{Therefore we have}\ y=-\dfrac{1}{5}x+b.\\\\\text{The line passing through the point (-2, 2).}\\\text{Put the coordinates of the point to the equation:}

2=-\dfrac{1}{5}(-2)+b\\\\2=\dfrac{2}{5}+b\qquad\text{subtract}\ \dfrac{2}{5}\ \text{from both sides}\\\\1\dfrac{3}{5}=b\to b=\dfrac{8}{5}\\\\\text{Therefore we have the equation of a line in slope-intercept form:}\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\\\\\text{Convert it to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{5}x+\dfrac{8}{5}\qquad\text{multiply both sides by 5}\\\\5y=-x+8\qquad\text{add x to both sides}\\\\\boxed{x+5y=8}\to\boxed{[B]}

8 0
3 years ago
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