The speed at which the stone hits the water is 13.6m/s and the initial height of the stone is 7.6m.
<h3 /><h3>Speed of stone as it hits the water</h3>
Initial velocity of stone = 6 ms⁻¹
At the maximum height, the final velocity, v = 0
Acceleration of the stone, g = 9.8 ms⁻²
Time taken to reach maximum height = t₁
t₁ = v - u/g
since the stone is travelling upwards, g = -9.8 m/s⁻²
t₁ = 0 - 6/-9.8
t₁ = 0.61 s
Time take to fall from maximum height, t = 2 - 0.61s
Time take to fall from maximum height = 1.39s
- Calculating the final velocity using the formula, v = u + gt
where u = 0 m/s
v = 0 + 9.8 * 1.39
v = 13.6 m/s
<h3>Initial height of stone</h3>
Initial height of stone = Height of bridge, H
Time taken by the stone to fall down from height, H in water, t = 2s
Initial velocity of stone = 6 ms⁻¹
Acceleration of the stone, g = 9.8 ms⁻²
- Height of the bridge, H = -ut + gt²/2
- Initial velocity is negative since it is against gravity
H = -6 * 2 + 9.8 * 2² /2
H = 7.6m
Therefore, the speed at which the stone hits the water is 13.6m/s and the initial height of the stone is 7.6m
Learn more about velocity and height at: brainly.com/question/13665920
