Speed is the rate at which something covers a distance; velocity is the same but it takes into account whether it goes forwards or backwards; and acceleration is the rate of an increase in speed.

8 0

3 years ago

Suppose a star has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 ) but is located at a distance of 300 ligh

iragen [17]

For a star that has the same apparent brightness as Alpha Centauri A ( 2.7×10−8watt/m2 is mathematically given as

L=2.7*10^30w

<h3> What is its luminosity?</h3>

Generally, the equation for the luminosity is mathematically given as

L=4*\pi^2*b

Therefore

L=4*\pi^2*b

L=4* \pi *(2.83*10^{18})*2.7*10^{-8}

L=2.7*10^30

In conclusion, the luminosity

L=2.7*10^30w

Read more about Light

brainly.com/question/25770676

6 0

1 year ago

What is the magnetic flux density (B-field) at a distance of 0.36 m from a long, straight wire carrying a current of 3.8 A in ai

olga nikolaevna [1]

Answer:

The magnetic flux density is $2.11\times10^{-6}\ T$

Explanation:

Given that,

Distance = 0.36 m

Current = 3.8 A

We need to calculate the magnetic flux density

Using formula of magnetic field

$B =\dfrac{\mu_{0}I}{2r}$

Where,

r = radius

I = current

Put the value into the formula

$B =\dfrac{4\pi\times10^{-7}\times3.8}{2\times\pi\times0.36}$

$B=2.11\times10^{-6}\ T$

Hence, The magnetic flux density is $2.11\times10^{-6}\ T$

3 0

2 years ago