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2 years ago

Please PLEASE HELP ASAP

Physics

1 answer:

Studentka2010 [4]2 years ago

3 0

Answer:

D) The tray would need to be raised higher before the items start to slide.

Explanation:

The tray would need to be raised higher due to the gritty sandpaper causing it to have more grip or fraction between the two surfaces. In the first experiment it would have a smooth surface to slide across but in the second experiment it would have a rougher surface to slide across.

Example: It would be like taking two different kinds of shoes like tennis shoes and football cleets. Then seeing which one has more traction when going up a hill.

Hope this helps!!

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The highest energy waves have the<br> {SHORTEST}wavelength

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_____________ forces are always attractive and the mass of an object determines how strong the ____________ pull is.

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Gravitational, gravitational ! both the option are same

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3 years ago

a system of four particles moves along one dimension. the center of mass of the system is at rest, and the particles do not inte

Zinaida [17]

The velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.

The given parameters;

m1 = 1.45 kg, v1(t) = (6.09m/s) + (0.299m/s^2) × t

m2 = 2.81 kg, v2(t) = (7.83m/s) + (0.357m/s^2) × t

m3 = 3.89 kg, v3(t) = (8.09m/s) + (0.405m/s^2) × t

m4 = 5.03kg

The velocity of the center mass of the particles is calculated as;

McmVcm = m1v1 + m2v2 +m3v3+m4v4

Vcm= m1v1 + m2v2 +m3v3 +m4v4/ Mcm

0 = m1v1 + m2v2 +m3v3 +m4v4/ Mcm

m1v1 + m2v2 +m3v3+m4v4 = 0

m4v4 = -(m1v1 + m2v2 +m3v3)

v4 =-(m1v1 + m2v2 +m3v3)/ m4

The velocity of particle 1 at time, t = 2.83 s;

vi = 6.09 + 0.299× 2.83

v1 = 6.94 m/s

The velocity of particle 3 at time, t = 2.83 s;

v2 = 7.83 + 0.357 × 2.83

v2 = 8.84 m/s

The velocity of particle 3 at time, t = 2.83 s;

v3 = 8.09 + 0.405 × 2.83

v3 = 9.24 m/s

The velocity of particle 3 at time, t = 2.83 s;

v4 = - (m1v1 + m2v2 + m3v3)/m4

v4 = -(1.45×6.94 + 2.81×8.84 + 3.89×9.24)/5.03

v4 = -14.4 m/s

Thus, the velocity of the particle 4 at time, t = 2.83 s, is -14.1 m/s.

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11 months ago

A football player kicks a 0.94 kg football with a force of 2.4 N.

Artyom0805 [142]

2.6m/s²

Explanation:

Given parameters:

Mass of football = 0.94kg

Force on ball = 2.4N

Unknown:

The acceleration of the ball = ?

Solution:

According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".

Net force = mass x acceleration

Make acceleration the subject of the expression;

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Acceleration = $\frac{2.4}{0.94}$ = 2.6m/s²

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2 years ago

Read 2 more answers

A displacement is related to time as x = A sin(2?ft), where A and f are constants. Find the dimensions of A. [Hint: A trigonomet

Luba_88 [7]

Answer:

The right option is C. i.e L

Explanation:

Dimension of a quantity is the collection of the indexes of each of the fundamental quantities contained in it.

Therefore, to get the dimension of A in the equation

X=Asin(2(pi)ft)

Making A the subject of the formula

A = X / (sin(2(pi)ft)

Since sin(2(pi)ft which is a trigonometric function does not have a dimension

A = L

The dimension of A is L

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3 years ago