Two trucks have the same velocity but different masses. Truck 1 has a mass of 200kg and truck 2 has a mass of 500kg . Which truc
1 answer:
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Answer:
The moment of inertia is
Explanation:
From the question we are told that
The frequency is
The mass of the pendulum is
The location of the pivot from the center is
Generally the period of the simple harmonic motion is mathematically represented as
Where I is the moment of inertia about the pivot point , so making I the subject of the formula it
=>
But the period of this simple harmonic motion can also be represented mathematically as
substituting values
So
Answer:
v = √2G / R
Explanation:
For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)
Eo = K + U = ½ m1 v² - G m1 m2 / r1
Ef = - G m1 m2 / r2
When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf
Eo = Ef
½ m1v² - G m1 / R = - G m1
/ R
v² = 2G (1 / R - 1 / Rinf)
If we do Rinf = infinity 1 / Rinf = 0
v = √2G / R
Ef = = - G m1 m2 / R
The mechanical energy is conserved
Em = -G m1 / R
Em = - G m1 / R
R = int ⇒ Em = 0