Work done = 0.5*m*[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.
Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,
Work done = 0.5 * 1.50 x 10^3 * ((-15)^2 - 25^2) = 3 x 10^5 joules
Just ignore the negative value for the final result because work is a scalar quantity.
You can estimate one more digit past the smallest division on the measuring device. If you look at a 10mL graduated cylinder, for example, the smallest graduation is tenth of a milliliter (0.1mL). That means when you read the volume, you can estimate to the hundredths place (0.01mL).
Answer:
The correct option is b) In galaxy clusters
Explanation:
A type of galaxy that appear elliptical in shape and have an almost featureless and smooth image is known as the elliptical galaxy.
An elliptical galaxy is three dimensional and consists of more than one hundred trillion stars which are present in random orbits around the centre.
Elliptical galaxy is generally found in the galaxy clusters.
The answer that is got 8.7 . I got that because if you divide 200 by 23 you get <span>8.69565217391 and if you round that you get 8.7</span>
Answer:
d. 1.69 * 10^6 N
Explanation:
Pressure is defined as force divided by area.
