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Allushta [10]
4 years ago
5

When temperature and pressure are applied to sedimentary and igneous rock?

Physics
1 answer:
spin [16.1K]4 years ago
6 0
Answer:

Igneous rock

Explanation:

Igneous rocks are formed through the cooling and solidification of magma. It undergoes changes in temperature and pressure that causes it to cool, solidify, and crystallize.
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Which type of graph is best for analyzing quantitative dependent and independent variables?
34kurt

Answer:

line graph

Explanation:

on edge

8 0
4 years ago
A force can best be defined as
lesya [120]
Force can best describe as push and pull of a certain object. It is due to some phenomena like gravity. Force is also present when a person exert forces or action. And also when a certain object moves it's momentum changes its rate.
Thus, all the given  choices are definition of force
5 0
3 years ago
A homemade capacitor is assembled by placing two 10-in. pie pans 2 cm apart by a piece of glass and connecting them to the oppos
valentina_108 [34]

Answer:

capacitance  =  2.242 × 10^{-11} F

charge = 1.345 × 10^{-10}  C

electric field = 600 V/m

work done = 8.07 × 10^{-10} J

Explanation:

given data

battery c = 12 V

diameter = 10 in

distance d = 2 cm = 2×10^{-2} m

to find out

capacitance , charge on plate, electric field and work done

solution

we know radius is diameter / 2

so radius r = 10 / 2 = 5 in = 0.127 m

and capacitance  formula that is

capacitance  = A∈/d

put here all value

capacitance  = πr² ∈/d

capacitance  = π(0.127)² ×8.85 ×10^{-12} /2×10^{-2}

capacitance  =  2.242 × 10^{-11} F

and

charge on plate is express as

charge = capacitance ×  c

we know here 2 plate so on  1 plate c is 6

charge = 2.242 × 10^{-11} ×  6

charge = 1.345 × 10^{-10}  C

and

electric field is express as

electric field = c / d

electric field = 12 / 2×10^{-2}

electric field = 600 V/m

and

work done is express as

work done = 1/2 × charge × C

put here value

work done = 1/2 × (1.345 × 10^{-10}) (12)

work done = 8.07 × 10^{-10} J

4 0
3 years ago
A compact fluorescent bulb is 17.0% efficient. How much energy input would be required for the bulb to produce 252 J of light en
Arisa [49]

Answer:

1482.35J

Explanation:

Efficency=(output energy/input energy) x100

17.0 =(252/input energy) x100

input energy =100x252/17=1482.35J

wasted energy=1482.35-252=1230.35J

3 0
3 years ago
As a box slides down a ramp, friction does 23.0 joules of work. At the bottom of the ramp, the box has 3.8 joules of kinetic ene
tensa zangetsu [6.8K]

Answer:

The high of the ramp is 2.81[m]

Explanation:

This is a problem where it applies energy conservation, that is part of the potential energy as it descends the block is transformed into kinetic energy.

If the bottom of the ramp is taken as a potential energy reference point, this point will have a potential energy value equal to zero.

We can find the mass of the box using the kinetic energy and the speed of the box at the bottom of the ramp.

E_{k}=0.5*m*v^{2}\\\\where:\\E_{k}=3.8[J]\\v = 2.8[m/s]\\m=\frac{E_{k}}{0.5*v^{2} } \\m=\frac{3.8}{0.5*2.8^{2} } \\m=0.969[kg]

Now applying the energy conservation theorem which tells us that the initial kinetic energy plus the work done and the potential energy is equal to the final kinetic energy of the body, we propose the following equation.

E_{p}+W_{f}=E_{k}\\where:\\E_{p}= potential energy [J]\\W_{f}=23[J]\\E_{k}=3.8[J]\\

And therefore

m*g*h + W_{f}=3.8\\ 0.969*9.81*h - 23= 3.8\\h = \frac{23+3.8}{0.969*9.81}\\ h = 2.81[m]

8 0
3 years ago
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