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sertanlavr [38]
3 years ago
16

Consider a system to be two train cars traveling toward each other. What is the total momentum of the system before the train ca

rs collide? kg • What must the total momentum of the system be after the train cars collide? kg •
Physics
2 answers:
Rudiy273 years ago
8 0

What is the total momentum of the system before the train cars collide?

 (1600) kg • ms

What must the total momentum of the system be after the train cars collide?

 (1600) kg •  ms

Brut [27]3 years ago
5 0

Let say the two train cars are of masses m_1 and m_2

now if the speed of two cars are v_1 and v_2

then we can say that the momentum of two cars before they collide is given by

P = m_1v_1 - m_2v_2

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.

Now since in these two car motion there is no external force on them while they collide

So the momentum of two cars are always conserved.

hence we can say that the final momentum of two cars will be same after collision as it is before collision

P = m_1v_1 - m_2v_2

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A block is hung by a string from the inside roof of a van. when the can goes straight ahead at a speed of 28 m/s, the block hang
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Answer:

θ =28.07⁰

Explanation:

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F_{c}= F_{n} sin\theta

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F_{n}cos\theta= mg----(2)

divide (1) and (2)

\frac{F_{n}sin\theta}{F_{n}cos\theta} = \frac{\frac{mv^{2} }{r} }{mg}

tan \theta=\frac{v^{2} }{rg}

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v = 28 m/s

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θ = 28.07⁰

5 0
3 years ago
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coas
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Answer:

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h_{A} = 100 m

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according to conservative energy

the distance from point A to B, h = 150 m - 100 m = 50 m

the initial speed v_{A}

final speed  v_{B} = 0

thus,

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0 = v_{A}² - 2 g h

v_{A}² = 2 g h

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