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2 years ago

Please help me I don’t have a lot of time

Mathematics

1 answer:

sp2606 [1]2 years ago

3 0

Answer:

I believe the answer is d

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Set up an equation to show (×+2)×5=y

Masteriza [31]

5x+10 = y

Subtract 10 from both sides.

5x = y - 10

Divide both sides by 5.

x = 1/5y - 2

Plugin 1/5y - 2 for the y.
5(1/5y - 2)
1 - 10 + 10 = y

1 = y

Your Answer(s)
y = 1
x = 1/5y - 2

4 0

3 years ago

Whats the answers to this question?

AnnyKZ [126]

Answer:

1) e = 6

2) w = 10

3) s = 27

4) t = 4

Step-by-step explanation:

Cross multiplication

3 0

2 years ago

When multiplied together, which two polynomials equal ab3+2a2b2? Select the two correct answers.

fomenos

The answer is 2) ab2 that would be ur answer

5 0

2 years ago

Read 2 more answers

What is the 3rd term in the sequence?

makvit [3.9K]

Answer:

Step-by-step explanation:

To find the third term substitute n = 3 into the n th term formula

a(3) = $\frac{3}{2}$ $(-2)^{3-1}$

= $\frac{3}{2}$ $(-2)^{2}$

= $\frac{3}{2}$ × 4 = 6

4 0

2 years ago

Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).

NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

$1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}$

Now, differentiate to obtain

$\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}$

$=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}$

To obtain the required form, extract a factor in both the numerator and denominator:

$\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)$

3 0

2 years ago