Answer:

Step-by-step explanation:


Let's solve for
in the first equation and then solve for
in the second equation.
I will then use the following identity to get right of the parameter,
:
(Pythagorean Identity).
Let's begin with
.
Subtract 2 on both sides:

Divide both sides by -3:

Now time for the second equation,
.
Subtract 1 on both sides:

Divide both sides by 4:

Now let's plug it into our Pythagorean Identity:




To add two functions, combine like terms. (5+3x^(3)) = 8x^3-2x. The domain is all real numbers. There is no bound on how small or large the numbers can be for cubed functions.
Answer:
okay
Step-by-step explanation:
Correct the first way is 1to1, 1:1, 1 boy to 1 girl .
Your answer should be 120