![\frac{x+3}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2B3%7D%7B12%7D%20)
=
![\frac{2}{7}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B7%7D%20)
Multiply both sides by 12, so that we get rid of the fraction in x.
12 · (x+3)/12 = 2/7 · 12
Simplify.
x + 3 = 24/7
Then, subtract 3 from both sides, so that "x" gets isolated.
x = 24/7 - 3
Turn "3" into an improper fraction so that we could find the value of x easier.
3 = 21/3
So :
x = 24/7 - 21/7
Simplify.
x = 3/7
~Hope this helps!~
Answer:
87.73 inches
Step-by-step explanation:
We are given that the dimensions of the rectangular doorway are,
Length = 6 ft 8 inches = 80 inches and Width = 3 feet = 36 inches.
Using Pythagoras Theorem, we will find the diagonal of the rectangular doorway.
i.e. ![hypotenuse^{2}=length^{2}+width^{2}](https://tex.z-dn.net/?f=hypotenuse%5E%7B2%7D%3Dlength%5E%7B2%7D%2Bwidth%5E%7B2%7D)
i.e. ![hypotenuse^{2}=80^{2}+36^{2}](https://tex.z-dn.net/?f=hypotenuse%5E%7B2%7D%3D80%5E%7B2%7D%2B36%5E%7B2%7D)
i.e. ![hypotenuse^{2}=6400+1296](https://tex.z-dn.net/?f=hypotenuse%5E%7B2%7D%3D6400%2B1296)
i.e. ![hypotenuse^{2}=7696](https://tex.z-dn.net/?f=hypotenuse%5E%7B2%7D%3D7696)
i.e. Hypotenuse = ±87.73 inches
Since, the length cannot be negative.
So, the length of the diagonal is 87.73 inches.
As, the largest side of a rectangle is represented by the diagonal.
So, the largest dimension that will fit through the doorway without bending is 87.73 inches.
Answer:
Tamara incorrectly factored the whole expression.
Step-by-step explanation:
Note that
- 21x=3·7·x;
- 56xy=2·2·2·7·x·y.
Mark in bold all common factors, then GCF(21x,56xy)=7·x=7x.
Thus,
21x+56xy=7x(3+8y).
Hence, Tamara correctly found the GCF of numbers 21 and 56, but incorrectly factored the whole expression.
Perimeter (P) = 2L + x
4900 = 2L + x ⇒ 4900 - x = 2L ⇒
= L
Area (A) = L · x
A = (
) (x)
= ![\frac{4900x - x^2}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4900x%20-%20x%5E2%7D%7B2%7D%20%20)
Answer:
16.5+13.6+12.4.17.7= 60.2
60.2÷4 =15.05