Answer:
Sometimes may cause involuntary responses like twitching
Explanation:
B) 48.0 m/s
We can actually start to solve the problem from B for simplicity.
The motion of the rock is a uniformly accelerated motion (free fall), so we can find the final speed using the following suvat equation

where
is the final velocity
is the initial velocity (positive since we take downward as positive direction)
is the acceleration of gravity
s = 110 m is the vertical displacement
Solving for v, we find the final velocity (and so, the speed of the rock at impact):

A) 3.67 s
Now we can find the time of flight of the rock by using the following suvat equation

where
is the final velocity at the moment of impact
is the initial velocity
is the acceleration of gravity
t is the time it takes for the rock to reach the ground
And solving for t, we find

The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
Learn more about force here:
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Answer :
<em>(b) 4d orbitals would be larger in size than 3d orbitals</em>
<em>(e) 4d orbitals would have more nodes than 3d orbitals</em>
Explanation :
As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.
Hence, 4d orbitals would be larger in size than 3d orbitals.
Number of nodes is any orbital is n - 1 where, n is principal quantum number.
So, number of orbital in 4d is 3.
And number of orbital in 3d is 2.
So, options (b) and (e) are correct.