A heavy flywheel is accelerated (rotationally) by a motor thatprovides constant torque and therefore a constant angularaccelerat
ion Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta. The flywheel is assumed to be at rest at timet = 0 in Parts A and B of this problem.a) Find the time t_1 it takes to accelerate the flywheel to omega_1 if the angular acceleration is Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta.Express your answer in terms ofomega_1 and Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta.b) Find the angle theta_1 through which the flywheel will have turned during thetime it takes for it to accelerate from rest up to angular velocityomega_1.Express your answer in terms of someor all of the following: omega_1, Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta, and t_1.Find the angle theta_1 through which the flywheel will have turned during thetime it takes for it to accelerate from rest up to angular velocityomega_1.Express your answer in terms of someor all of the following: omega_1, Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta, and t_1.c) Assume that the motor has accelerated thewheel up to an angular velocity omega_1 with angular acceleration Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta in time t_1. At this point, the motor is turned off and a brake isapplied that decelerates the wheel with a constant angularacceleration of -5. Find t_2, the time it will take the wheel to stop after the brakeis applied (that is, the time for the wheel to reach zero angularvelocity).Express your answer in terms of someor all of the following: omega_1, Image for A heavy flywheel is accelerated (rotationally) by a motor that provides constant torque and therefore a consta, and t_1.
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Answer:
The work required is -515,872.5 J
Explanation:
Work is defined in physics as the force that is applied to a body to move it from one point to another.
The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.
Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:
where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).
The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:
In this case:
- W=?
- m= 2,145 kg
- v2= 12
- v1= 25
Replacing:
W= -515,872.5 J
<u><em>The work required is -515,872.5 J</em></u>