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Answer:
The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.
See attachment below for full solution
Explanation:
This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.
Answer:
Length of pipe meter
Explanation:
Speed of a transverse wave on a string
where F is the tension in string and is the mass per unit length
Thus,
Substituting the given values we get -
Speed of a transverse wave on a string
For third harmonic wave , frequency is equal to
Substituting the given values, we get -
Length of pipe
Substituting the given values we get
for first harmonic wave
Length of pipe meter