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4 years ago

A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.

1 answer:

6 0

From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1
mm1 = 71/1.87²
= 71/3.4969
= 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon

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Concentrated hydrochloric acid is an aqueous solution that is 34.70 % HCl. The density of the solution is 1.19 g/mL. What mass o

mixas84 [53]

The mass of HCl that is contained in the solution is 147 g HCl

Why?

To find the mass of HCl we have to apply what is called a conversion factor. In a conversion factor we put the units we don't want at the bottom, and the ones we want at the top.

For this question, we want to go from liters of solution to mass of HCl, and the conversion factor is laid out as follows:

$0.356Lsolution*\frac{1000mL}{1L}*\frac{1.19 g solution}{1 mL solution}*\frac{34.70 g HCl}{100 g solution}=147 g HCl$

Have a nice day!

#LearnwithBrainly

3 0

4 years ago

how could you check that when the calcium carbonate is reacting with hydrochloric acid the gas given off is carbon dioxide

pav-90 [236]

Answer:

CaCO3 + 2 HCl => CaCl2 + CO2 + H2O

Explanation:

CO2 will burst out when the reaction occurs in water, and the ions will be dissociated: Ca(2+) + 2 Cl (-)

7 0

3 years ago

The initial concentration of reactant in a first-order reaction is 0.27 M. The rate constant for the reaction is 0.75 s−1. What

e-lub [12.9K]

Answer:

≈ 0.10M

Explanation:

[A]o = 0.27M

Rate constant, k = 0.75 s−1

[A] = ?

time, t = 1.3

Integrated formular for a first order reaction is given as;

ln[A] = ln[A]o − kt

ln[A] = ln(0.27) - 0.75(1.3)

ln[A] = -1.309 - 0.975

ln[A] = -2.284

[A] = 0.1019M ≈ 0.10M

4 0

4 years ago

Read 2 more answers

How many moles of LINO3 are

lidiya [134]

Answer:

Explanation:

number of moles = mass / molar mass
= 525 / 7+14+(3*14)
= 525 / 63
= 8.33 mol

4 0

2 years ago

What is the molarity of a 250ml KCl solution made by diluting 175mL of a 3.00 M solution?

Crank

Answer:

2.1 M

Explanation:

The dilution equation is $M_{s} V_{s} = M_{d} V_{d}$ .

$M_{s}$ = the molarity of the sock solution

$V_{s}$ = the volume of the sock solution

$M_{d}$ = the molarity of the diluted solution

$V_{d}$ = the volume of the diluted solution

The stock solution would be what is doing the diluting, so "175 mL of a 3.00 M solution". So $M_{s}$ = 3.00 M. Then: Converting 175 mL to liters: $175 mL * \frac{1 L}{1000mL} = 0.175 L$ (This is $V_{s}$ )

And converting 250 mL KCl to liters: $250 mL * \frac{1 L}{1000mL} = 0.250 L$ (This will be $V_{d}$ )

Then, we plug in our given into the dilution equation, resulting in:

$3.00 M * 0.175 L = M_{d} * 0.250 L$ (divide both sides by 0.250 L, in order to get $M_{d}$ by itself)

$\frac{3.00 M * 0.175 L}{0.250 L} = M_{d}$

$M_{d} = 2.1 M$

So, the molarity of 250 mL KCl made by diluting 175 mL of a 3.0 M solution would be 2.1 M (mol/L).

Hopefully this helped you understand the topic a little bit better. I just finished molarity and dilutions in Chemistry last week. Good luck!

4 0

3 years ago