<span>A scientific question is like a hypothesis. It's the question that you're trying to answer throughout the experiment. So, a scientific question in this case could be: If the car has bigger wheels, will it travel faster? This is something you can test in the experiment, by having different cars with different sized wheels. In this way, you can track how fast each car goes, and determine whether or not the wheel size increases speed, decreases speed, or has no effect on speed.</span>
Biuret reagent. This is the answer
Answer:
Metal
Explanation:
Lithium (Li), chemical element of Group 1 (Ia) in the periodic table, the alkali metal group, lightest of the solid elements. The metal itself—which is soft, white, and lustrous—and several of its alloys and compounds are produced on an industrial scale.
Atomic number: 3
Atomic weight: 6.941
Answer:
–0.16 m
Explanation:
From the question given above, the following data were obtained:
Time (t) = 0.18 s
Acceleration due to gravity (g) = –9.81 m/s²
Height (h) =?
We can obtain how far the ruler will fall by using the following equation:
H = ½gt²
H = ½ × –9.81 × 0.18²
H = ½ × –9.81 × 0.0324
H = –0.16 m
Thus, the ruler will fall –0.16 m before you will catch it.
Answer:
pH = 11.95≈12
Explanation:
Remember the reaction among aqueous acetic acid (
) and aqueous sodium hydroxide (NaOH)

First step. Need to know how much moles of the substances are present
= 0.0025 mol NaOH
0.003 mol NaOH *
/ 1 mol NaOH = 0.003 mol CH_3COOH[/tex]
NaOH is in excess. Now, how much?
0.003 mole NaOH - 0.0025 mole NaOH = 0.0005 mole NaOH
Then, that amount in excess would be responsable for the pH.
Third step. Know the pH
Remember that pH= -log[H+]
According to the dissociation of water equilibrium
Kw=[H+]*[OH-]= 10^(-14)
The dissociation of NaOH is
NaOH -> 
Now, concentration of OH^{-}[/tex] would be given for the excess of NaOH.
[OH-]= 0.0005 mole / 0.055 L = 0.00909 M
Careful: we have to use the total volumen
Les us to calculate pH
![pH= -log [H+]\\pH= -log \frac{K_w}{[OH-]} \\pH= 11.95](https://tex.z-dn.net/?f=pH%3D%20-log%20%5BH%2B%5D%5C%5CpH%3D%20-log%20%5Cfrac%7BK_w%7D%7B%5BOH-%5D%7D%20%5C%5CpH%3D%2011.95)