Answer:
67.91 g of CuCl2; 32.09 g of Cu.
Explanation:
The two masses add to 100.0 g, the initial amount of starting material, demonstrating the law of conservation of matter.
Answer:
9.85
Explanation:
M1V1 =M2V2
6.20×v1= 0.470×0.130
v1 = ( 0.470 × 0.130 ) ÷ 6.20
v1 = 0.0098 L × 1000
V1 = 9.8 ml
Answer:
2Cu + O2 ----------------> 2CuO
Answer:
Balanced reaction:
3 H2 (g) + N2 (g) → 2 NH3 (g)
Use stoichiometry to convert g of H2 to g of NH3. The process would be:
g H2 → mol H2 → mol NH3 → g NH3
12.0 g H2 x (1 mol H2 / 2.02 g H2) x (2 mol NH3 / 3 mol H2) x (17.03 g NH3 / 1 mol NH3) = 67.4 g NH3
Explanation: See above
Hope this helps, friend.
