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lukranit [14]
3 years ago
15

In a exothermic reaction, is heat transfered to or from the surrounding

Chemistry
2 answers:
Anna71 [15]3 years ago
8 0
Heat is transferred to the surrounding. To remember this just think heat EXits to the surrounding
Monica [59]3 years ago
7 0
In an exothermic reaction, heat is transferred to the surrounding.

Hope this helps, have a great day ahead!
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Write the electron configurations of these ions, potassium and magnesium
irinina [24]

Answer:

a

Explanation:

4 0
3 years ago
At STP, 32 grams of O2 would occupy the same volume as:
ludmilkaskok [199]

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

<h3>Further explanation</h3>

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

  • 4.0 g of He
  • 8.0 g of CH₄
  • 64 g of H₂
  • 32 g of SO₂

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

\tt \dfrac{32}{32}=1

  • He

\tt mol=\dfrac{4}{4}=1

  • CH₄

\tt mol=\dfrac{8}{16}=0.5

  • H₂

\tt mol=\dfrac{64}{2}=32

  • SO₂

\tt mol=\dfrac{32}{64}=0.5

<em>So mol of 4 g He = mol of 32 g O₂</em>

4 0
3 years ago
The molar mass of aniline is 93 g/mol. what is its molecular formula
Mashutka [201]

Answer:

Molecular formula of aniline is C6H5NH2.

Explanation:

As we know, molecular mass can be calculated as

Molar mass =  C6H5NH2

Molar mass = (6*12)+(1*7)+(28)

Molar mass  = 93 g/mol

4 0
3 years ago
The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H
Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f\times m

or,

\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}

where,

\Delta T_f = change in freezing point

k_f = freezing point constant  (for benzene} =5.12^0Ckg/mol

m = molality

Putting in the values we get:

0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}

{\text{ Mass of solute in g}}=0.028g

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

4 0
3 years ago
Can I please know What are the answers for #s 1,2,3,4 ?
dimulka [17.4K]
1 wavelength, 2 crest, 3 trough, 4 wave height <3
8 0
3 years ago
Read 2 more answers
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