Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
Answer: Hahahhahahaha
Explanation:
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I hope this helps you
5 1/2=5.2+1/2=11/2
3.11/2
33/2
15 3/2
16,5
If you would like to write 0.423 as a percent, you can calculate this using the following step:
0.423 * 100% = 42.3%
The correct result would be 42.3%.
Answer:
PEMDAS
[(30+6)-3^2] ÷ by 9·2
[(30+6)-9] ÷ by 9·2
[(36)-9] ÷ by 9·2
(27) ÷ by 9·2
Division comes first in this equation. Multiplication & Division goes from left to right when using PEMDAS. Same thing goes for Addition & Subtraction.
[(27) ÷ 9] · 2
(3) · 2
Answer: 6
Hopefully that made sense!
Step-by-step explanation:
