Answer:
D. 9
Step-by-step explanation:
Let
abc=100a+10b+c
bca=100b+10c+a
cab=100c+10a+b
abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)
=100a + 10b + c + 100b + 10c + a + 100c + 10a + b
Collect like terms
=100a + a + 10a + 10b + 100b + b + c + 10c + 100c
=111a + 111b + 111 c
Factorise
=111(a+b+c)
abc + bca + cab = 111(a+b+c)
Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)
abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)
abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)
abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)
abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)
230 divided by 2 is 115
Hope that helped :)
Answer:
Step-by-step explanation:
Since the denominator of each of those rational exponents is a 4, that means that the radical is a 4th root. The numerator of each exponent serves as the power on the given base. For example,
can be rewritten as
![\sqrt[5]{2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E3%7D)
The little number that sits outside the radical, resting in the bend, is called the index. Our index is 4 (same as saying the 4th root). Put everything under the 4th root and let the numerator be the powers on each base:
![\sqrt[4]{6^1*b^3*c^1}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B6%5E1%2Ab%5E3%2Ac%5E1%7D)
which is written simpler as:
![\sqrt[4]{6b^3c}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B6b%5E3c%7D)
Answer:
83.4
Step-by-step explanation:
Area of a Regular Polygon: L (of side) times apothem (height) x 1/2
L : 13.9
Looking at the triangle we can assume the height would be 12 since its logical that 3 of the 4 lines can fit in the middle of the triangle.
H: 12
13.9 x 12 = 166.8
166.8/2 = 83.4
Answer:
800 in²
Step-by-step explanation:
Applying,
TSA (A) = Area of the base+ Lateral area of the
A = lw+1/2ps................ Equation 1
Where l = lenght of the base, w = width of the base, p = perimeter of the base, s = slight height of the base.
But,
p = 2(l+w)............. Equation 2
Substitute equation 2 into equation 1
A = lw+1/2[2(l+w)s)
A = lw+s(l+w)............. Equation 3
From the question,
Given: l = 16 in, w = 16 in, s = 17 in
Substitute these values into equation 3
A = (16×16)+17(16+16)
A = 256+544
A = 800 in²
