At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
<h3>What is Henry's Law ?</h3>
Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.
<h3>What is relationship between Henry's Law constant and Solubility ?</h3>
The solubility of gas is directly proportional to partial pressure.
It is expressed as:

where,
= Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now put the values in above expression we get

0.080M =
× 1.7 atm

= 0.047 M/atm
Now we have to find the partial pressure of He

0.200 M = 0.047 M/atm × 

= 4.25 atm
Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
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Answer:
The heart and the blood vessels are a part of the circulatory system. The blood vessels include the arteries, veins and capillaries. The lungs are considered to be the pulmonary part of the circulatory system. The heart is the cardiovascular part of the circulatory system and the vessels are the systemic part of the circulatory system. The main function of the circulatory system is to supply all parts of the body with oxygenated blood and to take away the deoxygenated blood from all parts of the body.
Answer : The partial pressure of
at equilibrium is, 1.0 × 10⁻⁶
Explanation :
The partial pressure of
= 
The partial pressure of
= 
The partial pressure of
= 

The balanced equilibrium reaction is,

Initial pressure 1.0×10⁻² 2.0×10⁻⁴ 2.0×10⁻⁴
At eqm. (1.0×10⁻²-2p) (2.0×10⁻⁴+p) (2.0×10⁻⁴+p)
The expression of equilibrium constant
for the reaction will be:

Now put all the values in this expression, we get :


The partial pressure of
at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶
Therefore, the partial pressure of
at equilibrium is, 1.0 × 10⁻⁶
The relative formua for Potassium bromide is Kbr