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Juliette [100K]
3 years ago
13

Write a net ionic equation to show that hydroiodic acid, hi, behaves as an acid in water.

Chemistry
2 answers:
Marianna [84]3 years ago
7 0

The answer is:

HI (aq) + H₂O (ℓ) ⟶ H₃O⁺ (aq) + I⁻ (aq)

<h2>Further Explanation </h2>

In chemistry, the equation of a reaction or chemical equation is the symbolic writing of a chemical reaction. The chemical formula of the reagent is written to the left of the equation and the chemical formula of the product is written to the right. The coefficient written to the left of a chemical formula is a stoichiometric coefficient, which describes the amount of that substance involved in a reaction relative to another substance. The reaction equation was first made by the iatrochemist Jean Beguin in 1615. In a reaction equation, reagents and products are connected by different symbols. The symbol → is used for one-way reactions, ⇆ for two-way reactions, and ⇌ equilibrium reactions.

Clean ionic equations are important aspects for chemistry because these equations only represent the states of matter that change in chemical reactions. This equation is commonly used in redox reactions, double replacement reactions, and acid-base neutralization. There are three basic steps to writing a clean ionic equation: balancing a molecular equation, converting it into a fully ionic equation (how each type of substance is in solution), and Determining the cations and anions in a compound.

1. equalizing molecular equations

The first step to writing a clean ionic equation is to identify the ionic compounds from the reaction. Ionic compounds are compounds that will ionize in aqueous solution and have a charge. Molecular compounds are compounds that have never had a charge. These compounds are formed from two nonmetals and are often referred to as covalent compounds.

Ionic compounds can be formed from metals and non-metals, metal and polyatomic ions, or some polyatomic ions.

If you are not sure about a compound, look for elements of the compound in the periodic table.

2. transform into a fully ionic equation

Not all ionic compounds can dissolve in aqueous solutions. Thus, the compound will not dissolve into individual ions. You must identify the solubility of each compound before continuing the rest of the equation. The following is a summary of the rules regarding solubility.

3. Determine the cations and anions in a compound

Cations are positive ions in a compound and are usually metals. Anions are nonmetal negative ions in compounds. Some non-metals can form cations, but metals will always form cations.

Learn more

definition of chemical equation brainly.com/question/11575465

three basic steps to writing a clean ionic equation brainly.com/question/11575465

Details

Grade: College

Subject: Chemistry

keywords: chemical equation

OlgaM077 [116]3 years ago
3 0

Answer:

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Explanation:

The HI donates a proton to the water, converting it to a hydronium ion

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Thus, the HI is behaving like a Brønsted acid.

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Two liters of hydrogen gas are stored at a
Tju [1.3M]

Answer:

the volume will expand

Explanation:

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6 0
2 years ago
A 25.00 ml solution of sulfuric acid H2SO4 is titrated to phenolphthalein end point with 27.00 ml of 1.700 M KOH
Nastasia [14]
<h3>Answer:</h3>

0.918 M

<h3>Explanation:</h3>

Assuming the question requires we calculate the Molarity of sulfuric acid:

We are given:

  • Volume of the acid, H₂SO₄ = 25.00 ml
  • Volume of the base, KOH = 27.00 mL
  • Molarity of the base, KOH is 1.70 M

We can calculate the molarity of the acid using the following steps;

<h3>Step 1: Write the chemical equation for the reaction.</h3>

The reaction is an example of a neutralization reaction where a base reacts with an acid to form salt and water.

Therefore, the balanced equation will be;

H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)

<h3>Step 2: Determine the moles of the base, KOH </h3>

When given molarity and the volume of a solution, the number of moles can be calculated by multiplying molarity with volume.

Number of moles = Molarity × Volume

                             = 1.700 M × 0.027 L

                              = 0.0459 moles

Thus, moles of KOH used is 0.0459 moles

<h3>Step 3: Determine the number of moles of the Acid, H₂SO₄</h3>

From the reaction, 1 mole of the acid reacts with 2 moles of KOH

Therefore, the mole ratio of H₂SO₄ to KOH is 1 : 2

Thus, moles of H₂SO₄ = Moles of KOH ÷ 2

                                     = 0.0459 moles ÷ 2

                                     = 0.02295 moles

<h3>Step 4: Calculate the molarity of the Acid </h3>

Molarity is the concentration of a solution in moles per liter

Molarity = Moles ÷ Volume

Molarity of the acid = 0.02295 moles ÷ 0.025 L

                                = 0.918 M

Thus, the molarity of the acid, H₂SO₄ is 0.918 M

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