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madam [21]
3 years ago
7

A hotel must increase its price by 5% per night, if the new price is $168 per night. What was the original cost?

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
5 0

Hey there! I'm happy to help!

We see that if you add 5% to the original cost, we have $168 as our cost. This means that 105% of the original cost is 168. Let's set up an equation to find the original cost. Let's call our original cost c.

To turn a percent into a decimal, you divide by 100.

1.05c=168

We divide both sides by 1.05.

c=160

Therefore, the original cost was $160.

Have a wonderful day! :D

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Answer:

\lim_{x \to 10^+} h(x) = 18.5

Step-by-step explanation:

As x approaches 10 from the right side, h(x) approaches 18.5 but never touches it.

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How many miles is 2/3
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=2/3*1760

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hope this helps

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Write the following as an inequality 6 is greater than or equal to x and -2 is less than or equal to x
kipiarov [429]

Answer:

  -2 ≤ x ≤ 6

Step-by-step explanation:

The first is ...

  6 ≥ x

and it can also be written as ...

  x ≤ 6

The second is

  -2 ≤ x

The two inequalities can be combined into one compound inequality:

  -2 ≤ x ≤ 6

_____

<em>Comment on this answer</em>

I prefer the answer in this form because it puts the parts of the expression in the same order that they appear on a number line. It can also be written as ...

  6 ≥ x ≥ -2

7 0
4 years ago
Find the steady periodic solution to the differential equation x′′+2x′+64x=7sin(7t) in the form xsp(t)=ccos(ωt−α), with c &gt; 0
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7 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
3 years ago
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