Complete Question
A skier leaves a ski jump with a horizontal velocity of 29.4 m/s. The instant before she lands three seconds later, the magnitudes of the horizontal and vertical components of her velocity are: Group of answer choices
A 29.4 m/s; 29.4 m/s.
B 41.6 m/s; 41.6 m/s.
C 29.4 m/s; 41.6 m/s.
D 0; 29.4 m/s.
E 29.4 m/s; 0.
Answer:
Correct option is A
Explanation:
From the question we are told that
The horizontal velocity is
The time taken for the jump is
The velocity along the vertical axis is
substituting values
During the jump the horizontal velocity remains the same as there was a direction change
So the correct option is A
Answer:
Explanation:
From the equation we are told that:
Velocity of French sub
Velocity of U.S. sub at
French Wave Frequency
Velocity of wave
Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by
Doppler effect
Answer:
Explanation:
a )
in the regions r < R₁
charge q inside sphere of radius R₁ = 0
Applying gauss's law for electric field E at distance r <R₁
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q / ε₀ = 0 / ε₀
E = 0
Applying gauss's law for electric field E at distance R₁ < r < R₂ .
charge q inside sphere of radius R₁ = q₁
Applying gauss's law for electric field E at distance R₁ < r < R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q₁ / ε₀
E = q₁ / 4πε₀
in the regions r> R₂
charge q inside sphere of radius R₂ = (q₁ + q₂)
Applying gauss's law for electric field E at distance r > R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = (q₁ + q₂) / ε₀
E = (q₁ + q₂) /4π ε₀
b )
For electric flux to be zero at r > R₂
(q₁ + q₂) /4π ε₀ = 0
q₁ + q₂ = 0
q₁ / q₂ = - 1 .
Answer:
Explanation:
spring constant of spring = mg / x
= .4 x 9.8 / ( .95 - .65 )
=13.07 N / m
energy stored in spring = 1/2 k x²
= .5 x 13.07 x ( 1.2 - .65 )²
= 1.976 J
Let it goes x m beyond its equilibrium position
Total energy at initial point
= 1.976 + 1/2 m v²
= 1.976 + .5 x .4 x 1.6²
= 2.488 J
energy at final point
= mgh + 1/2 k x²
.4 x 9.8 x ( .55 + x ) + .5 x 13.07 x² = 2.488
6.535 x² + 2.156 + 3.92 x = 2.488
6.535 x² + 3.92 x - .332 = 0
x = .075 m
7.5 cm
He did sadly can’t believe it T-T