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vladimir2022 [97]
3 years ago
13

How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?

Physics
2 answers:
viva [34]3 years ago
8 0

The energy released when a certain amount of a substance condenses to a liquid is given by:

Q=m \lambda_v

where m is the mass of the substance and \lambda_v is the latent heat of vaporization.

In this problem, the mass is m=0.06 kg, while the latent heat of vaporization of mercury is \lambda_v=296 kJ/ kg. Therefore, if we apply the formula we get:

Q=(0.06 kg)(296 kJ/ kg)=17.76 kJ=17760 J

So, the correct answer is

C. 17,705.1 J

zvonat [6]3 years ago
7 0
The answer is ....  C. 17,705.1 J
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μ = (3 x 10^8) / (2.26 x 10^8)

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3 years ago
Ratio of resistances of two bulbs is 2:3. If they are connected in series to a supply, then the ratio of voltages across them is
V125BC [204]

Answer:

Explanation:

Given that,

Two resistor has resistance in the ratio 2:3

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R1 / R2 =⅔

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Let R2 = R

Then,

R1 = ⅔R2 = 2/3 R

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Series connection will have a equivalent resistance of

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Req = R + ⅔ R = 5/3 R

Req = 5R / 3

Let a voltage V be connect across then, the current that flows can be calculated using ohms law

V = iR

I = V/Req

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I = 3V / 5R

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V= iR

For R1 = ⅔R

V1 =i•R1

V1 = 3V / 5R × 2R / 3

V1 = 3V × 2R / 5R × 3

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V2 = i•R2

V2 = 3V / 5R × R

V2 = 3V × R / 5R

V2 = 3V / 5

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Ratio of voltage 1 to voltage 2

V1 : V2 = V1 / V2 = 2V / 5 ÷ 3V / 5

V1 : V2 = 2V / 5 × 5 / 3V.

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