repal postive to postive or negitve to negtive
That was Johannes Kepler.
He couldn't say why that should happen. But he was able to show that
if we <em><u>assume</u></em> the the sun is in the center of the solar system, and <em><u>assume</u></em>
that the planets revolve around the sun in elliptical orbits, and <em><u>assume</u></em> that
the farther a planet is from the sun the longer it takes to orbit the sun, then
<em>that matches everything that we see the planets actually doing in the sky</em>.
Then Isaac Newton came along, and wrote down a short, simple formula
for the force of gravity. And then he showed that <u>IF</u> his formula for gravity
is correct, then the planets MUST do everything that we see them actually
doing in the sky, and they MUST behave according to Kepler's laws.
Wotta guy !
Answer:
Oxidative phosphorylation
Explanation:
This takes place mostly in the organelle called the mitochondrion.
Oxidation of nutrients in cells by enzymes results in the release of the chemical energy present in the molecular energy.
The NADH and succinate products of the citric acid cycle are also oxidized. All this series of reactions takes place in the Electron transport system.The energy from the oxidation is used to produce adenosine triphosphate (ATP) hence the name oxidative phosphorylation.
Question:
A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?
Answer:
Time for the race will be t = 9.26 s
Explanation:
Given data:
As the sprinter starts the race so initial velocity = v₁ = 0
Distance = s₁ = 20 m
Acceleration = a = 4.20 ms⁻²
Distance = s₂ = 100 m
We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.
Using 3rd equation of motion
(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)
v₂ = 12.96 ms⁻¹
Time for 20 m distance = t₁ = (v₂ - v ₁)/a
t₁ = 12.96/4.2 = 3.09 s
He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be
Time for 100 m distance = t₂ = s₂/v₂
t₂ = 80/12.96 = 6.17 s
Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s
T = 9.26 s
Here’s a good photo to reference when converting in the metric system.
Each time you move down a step you move the decimal to the right, each time you move up a step you move the decimal to the left.
We are going from 1.2 kg or kilograms, which is at the very top left of the ladder. To get to mg or milligrams, we would have to make six jumps, so we’d move the decimal over six times.
1.2 > 12. > 120. > 1200. > 12000. > 120000. > 1200000.
So our final answer would be 1,200,000mg.
