A 331 N stoplight is hanging in equilibrium from cables as shown. The tension in the right cable is 550 N, and it makes an angle
1 answer:
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(if it's frictionless the length doesn't even matter :) )
It would have the same kinetic energy down as the potential energy up. That is,
or 
(the mass doesn't even matter). The result is 
, so only the height matters really. It is almost 9 (it is 
).
It would have the same kinetic energy down as the potential energy up. That is,
Answer:
the work done by gravity on the boy is 604.62 J
Explanation:
Given;
distance the boy slides, d = 3 m
angle of inclination of the playground, θ = 40⁰
mass of the boy, m = 32 kg
The vertical height, h, above the ground through which the boy falls represents the height of the triangle which is the opposite side.
The distance through which the boy slides, d, represents the hypotenuse side of the right triangle.
The work done by gravity on the boy is calculated as;
W = P.E = mgh
= 32kg x 9.8m/s² x 1.928m
= 604.62 J
Therefore, the work done by gravity on the boy is 604.62 J